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kobusy [5.1K]
4 years ago
15

Which is not something submersibles do?

Chemistry
2 answers:
SOVA2 [1]4 years ago
8 0

-QUESTION-

Which is not something submersibles do?


-OPTIONS-

A. Collect data about areas of the ocean that were previously unreachable by humans.

B. Remain under water for long periods of time.

C. Collect data about shoreline cliffs, waves, and measurable atmospheric effects.


-ANSWER-

<u><em>C. COLLECT DATA ABOUT SHORELINE CLIFFS, WAVES, AND MEASURABLE ATMOSPHERIC EFFECTS.</em></u>


<em>I hope i helped have an amazing day.......</em>

<em>~PICKEL519</em>

astraxan [27]4 years ago
4 0
<span>Collect data about shoreline cliffs, waves, and measurable atmospheric effects.</span>
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What were the defects in Ruther Ford Atomic model?
juin [17]

the RutherFord atomic model has the limitations in explaining the stability of the atom and the stability of the electron.

<u>Explanation:</u>

  • As we know basically the atom comprises of the positively charged proton and negative charge electron and no charge neutron.
  • In these particles, electron revolves with the nucleus as a centre in the orbit with the different energy levels.
  • So by this revolving action, there will be the loss of energy and thus electrons are to be falling into the nucleus which affects the stability of the electron.  
  • The atom is said to be neutral electrically if the protons and electrons are equal. So in the above case if the electrons on losing the energy if it fells into the nucleus, as a result, the stability of the atom is affected which makes the atom as ions.
7 0
3 years ago
Describe the orbital notation and electron configuration notation to describe the placement of all of the electrons in an atom o
andriy [413]
The arrangement of the electrons on the orbitals is governed by the principles of quantum energy. To be able to draw the correct electronic configuration of an element, they should follow these three principles.

1. Aufbau's Principle. The electrons of an element should be filled up from the highest energy level. You can use the periodic table as a guide for this. In decreasing order, the energy of the orbitals are 1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 5s, 4d, 5p, 6s, 4f, 5d, 6p, 7s, 5f, 6d and 7p. Each 'box' of these orbital must be filled with two electrons from 1s before moving on to the next.

2. Hund's rule. This states that you must fill all boxes of one orbital with one electron first. For example, 2p has 3 boxes. You fill one electron for each box first before going back to fill it to two electrons if there are still excess.

3. Pauli's Exclusion Principle. This states that no electrons of the same element should have the same quantum numbers. To achieve this, the two electrons in each box should have opposite spins, one facing up, and the other facing down.

Using these three rules, you will be able to draw the electronic configuration of Fluorine with 9 electrons as shown in the picture.

7 0
3 years ago
Which property is shared by both acids and bases?
Evgen [1.6K]

\huge{\textbf{\textsf{{\color{navy}{An}}{\purple{sw}}{\pink{er}} {\color{pink}{:}}}}}

3. Conducts electricity in aqueous solution.

  • Thanks
  • Hope it helps.
3 0
3 years ago
what is the relative atomic mass of a hypothetical element that consists of the following isotopes in the indicated natural abun
natulia [17]

Answer:

87.3

Explanation:

To calculate the relative atomic mass

((84.9*15)+(86.9*12.9)+(87.9*72.1))/15+12.9+72.1

(1273.5 + 1121.01 + 6337.59) / 100

8732.1/100

87.321 = 87.3

6 0
3 years ago
If the ka of a monoprotic weak acid is 5.4 × 10-6, what is the ph of a 0.14 m solution of this acid?
Aleks [24]

pH = 2.1

Let HA (aq) resembles the acid; as a weak acid (a small value of K_{a}) HA would partially dissociate to produce protons H^{+} and A^{-}, its conjugate base. Let the final proton concentration (i.e., [H^{+}]) be x. (Apparently x \ge 0) Construct the following RICE table:

\left\begin{array}{cccccc}\text{R}&HA(aq)&\rightleftharpoons&H^{+}(aq) &+ &A^{-}(aq)\\\text{I} & 0.14 \; \text{M} & &\\\text{C}&-x \; \text{M}& &+x \; \text{M} & & +x \; \text{M}\\E & (0.14 - x)\; \text{M} & & x \; \text{M} & &\+x \; \text{M}\end{array}\right

By definition, (all concentrations are under equilibrium condition)

\left\begin{array}{ccc}K_{a}&=&[H^{+}] \cdot [A^{-}] / [HA]\\&=&x^{2} /(0.14 - x)\end{array}\right

It is given that

K_a = 5.4 \cdot 10^{-6}

Equating and simplifying the two expressions gives a quadratic equation; solve the equation for x gives:

x^2 = 5.4 \cdot 10^{-6} \cdot (14 - x) \\x^2 + 5.4 \cdot 10^{-6} \cdot 14 \cdot x - 5.4 \cdot 10^{-6} \cdot 14 = 0 \\x = 0.0087 \; \text{M} \; (x \ge 0)

The pH of a solutions equals the opposite of the logarithm of its proton concentration to base 10; thus for this particular solution

\text{pH} = -\text{ln(}[H^{+}]\text{)} / \text{ln(}10\text{)} = 2.1

7 0
4 years ago
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