Answer:
Explanation:
The common application of indicators is the detection of end points of titrations. The colour of an indicator alters when the acidity or the oxidizing strength of the solution, or the concentration of a certain chemical species, reaches a critical range of values.
Answer:
B
Explanation:
exo - thermic exo as external thermo like thermometer
external heat....heat is produced and given off
Explanation:
Im not sure what the other trait is so I couldn't do phenotype. I hope this still helps though
Answer:
Explanation:
given that
mass of Ba(NO3)2 = 1.40g
mass of NH2SO3H = 2.50 g
1)to determine the mole of Ba(NO3)2
2) to determine the mass of all three product formed in the reaction
reaction
Ba(NO3)2 + 2NH2SO3H → Ba(NH2SO3)2 + 2HNO3
<u>Solution</u>
we calculate the molar mass of each species by using their atomic masses
BA = 137.33g/mol
N = 14g/mol
O= 16g/mol
H = 1g/mol
S = 32g/mol
calculation
Ba(NO3)2 = Ba + 2N + 6O
= 137.33 + 2X 14 + 6 X 16
= 261.33g/mol
NH2SO3H = N + 3H + S+ 3O
=14 + 3X1 + 32 + 3X 16
= 97g/mol
Ba(NH2SO3)2 = Ba + 2N + 4H +2S +6O
= 137.33 + 2 X 14 + 4 X1 + 2X32 + 6 X 16
= 329.33g/mol
HNO3 = H + n + 3O
= 1 + 14 + 3 X 16
= 63g/mol
Answer:
116.88 g
Explanation:
Step 1: Write the balanced equation for the synthesis of NaCl
Na + 1/2 Cl₂ ⇒ NaCl
Step 2: Calculate the moles corresponding to 45.978 g of Na
The molar mass of Na is 22.990 g/mol.
45.978 g × 1 mol/22.990 g = 1.9999 mol
Step 3: Calculate the number of moles of NaCl formed from 1.9999 moles of Na
The molar ratio of Na to NaCl is 1:1. The moles of NaCl formed are 1/1 × 1.9999 mol = 1.9999 mol.
Step 4: Calculate the mass corresponding to 1.9999 moles of NaCl
The molar mass of NaCl is 58.443 g/mol.
1.9999 mol × 58.443 g/mol = 116.88 g
