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melamori03 [73]
3 years ago
7

A shopaholic has to buy a pair of jeans , a pair of shoes l,a skirt and a top with budgeted dollar.Given the quantity of each pr

oduct and the price per unit determine how many options of each item are present.if required all dollars are spent write the programming in c​
​
Engineering
1 answer:
fredd [130]3 years ago
0 0

Answer:

you might be facing some difficulty in observing this point of division between your question and me

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A 4-stroke Diesel engine with a displacement of Vd = 2.5x10^-3m^3 produces a mean effective pressure of 6.4 bar at the speed of
yKpoI14uk [10]

Answer:

The power developed by engine is 167.55 KW

Explanation:

Given that

V_d=2.5\times 10^{-3} m^3

Mean effective pressure = 6.4 bar

Speed = 2000 rpm

We know that power is the work done per second.

So

P=6.4\times 100\times 2.5\times 10^{-3}\times \dfrac{2\pi \times2000}{120}

We have to notice one point that we divide by 120 instead of 60, because it is a 4 cylinder engine.

P=167.55 KW

So the power developed by engine is 167.55 KW

4 0
3 years ago
PLS HELP!!!
Advocard [28]

Answer:

I would say C

Explanation:

let me know if im right

3 0
2 years ago
Read 2 more answers
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leonid [27]

Answer=

low-frequency EMFs pose little danger to human health. ... Exposure to large levels of high-frequency EMFs is known to damage human DNA and cells

Explanation:

8 0
3 years ago
What could be used as another word for electrical potential?
Marat540 [252]

Answer: C. Voltage

Explanation:

Here are some other words as well.

potential, voltage, potential drop, potential difference.

Answered by the ONE & ONLY #QUEEN aka #DRIPPQUEENMO!!!

HOPE THIS HELPED!!!

6 0
2 years ago
A polyethylene rod exactly 10 inches long with a cross-sectional area of 0.04 in2 is used to suspend a weight of 358 lbs-f (poun
Nadya [2.5K]

Answer:

Final length of the rod = 13.90 in

Explanation:

Cross Sectional Area of the polythene rod, A = 0.04 in²

Original length of the polythene rod, l = 10 inches

Tensile modulus for the polymer, E = 25,000 psi

Viscosity, \eta = 1*10^{9} psi -sec

Weight = 358 lbs - f

time, t = 1 hr = 3600 sec

Stress is given by:

\sigma = \frac{Force}{Area} \\\sigma = \frac{358}{0.04} \\\sigma = 8950 psi

Based on Maxwell's equation, the strain is given by:

strain = \sigma ( \frac{1}{E} + \frac{t}{\eta} )\\Strain = 8950 ( \frac{1}{25000} + \frac{3600}{10^{9} } )\\Strain = 0.39022

Strain = Extension/(original Length)

0.39022 = Extension/10

Extension = 0.39022 * 10

Extension = 3.9022 in

Extension = Final length - Original length

3.9022 =  Final length - 10

Final length = 10 + 3.9022

Final length = 13.9022 in

Final length = 13.90 in

7 0
3 years ago
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