Which design activity is part of the design for manufacturability (DFM) methodology?

How does data mining help interactive marketing for a business?

ser-zykov [4K]

The way in which data mining helps interactive marketing for a business firm is: D. By predicting what each individual accessing a website is most likely interested in seeing.

<h3>What is data mining?</h3>

Data mining can be defined as a strategic process that typically involves extracting and analyzing data that are contained in large databases, especially through the use of specialized software to generate new information.

In this context, a business firm can adopt the use of data mining to enhance and facilitate interactive marketing by creating a process that can effectively and efficiently predict what each individual (customer) accessing their website is most likely interested in seeing.

Read more on a website here: brainly.com/question/26324021

7 0

2 years ago

Pine Valley Furniture wants to use Internet systems to provide value to its customers and staff. There are many software technol

qaws [65]

Answer:

In these present generation, every day a new technology is coming. People are adopting these technologies very fast. If we think ," we have learned C language , now why to worry about java " . Then that is called you are bounding yourself to a technology. You are not ready for the growth.

With the invent of new technologies, if we have basic idea of how it works, we can simply implement it. At the end of day , it doesn't really matter how many lines of code you have written , it is just about efficiency. How Efficiently you are writing your code.

So, When Efficiency is the only thing that matters to the organizations , they are ready to take up new technologies and they will try to work-out with them. This is the trend in IT .Every month a new technology comes, respective people will be trained on that and they will implement/migrate the existing projects into new efficient model.

If we really learn and implement things using advance technologies , people will get an exposure to new technologies as well as the organization will get good impact on them , for spending resources on learning new technologies in the market. Apart from that , everyone will be happy for adopting new stack of technologies for them.

If we observe the existing technologies:

Programming languages are :

C, JAVA, PYTHON,R , SCALA

web development technologies:

HTML,CSS , JAVASCRIPT, ANGULAR,REACT , BOOTSTRAP , NODE.JS, MongoDB....etc

databases skills:

SQL, oracle,mySQL, postgres and so many cloud databases also available.

So, there are plenty of opportunities that are available . There are life time courses available to learn new technologies.

LEARN..RELEARN....UNLEARN

this is the motto of many organizations. They simply learn one technology and they'll forget it . If something new comes, they'll learn and implements it.This is the current trend in software industry.

3 0

3 years ago

An important ethical concern for behavior analysts involves special cautions in interactions with a client in any capacity outsi

Phoenix [80]

Answer:A and B are correct. one must take care to avoid violation of ethical codes regarding conflicts of interest and dual or multiple relationships

Explanation:

A conflict of interest (COI) is a situation in which a person or organization is involved in multiple interests, financial or otherwise, and serving one interest could involve working against another.

4 0

2 years ago

Is santa real or nah is santa real or nah

Elena L [17]

Answer:

nah

Explanation:

3 0

3 years ago

Read 2 more answers

An alloy is evaluated for potential creep deformation in a short-term laboratory experiment. The creep rate (ϵ˙) is found to be

cupoosta [38]

Answer:

Activation energy for creep in this temperature range is Q = 252.2 kJ/mol

Explanation:

To calculate the creep rate at a particular temperature

creep rate, $\zeta_{\theta} = C \exp(\frac{-Q}{R \theta} )$

Creep rate at 800⁰C, $\zeta_{800} = C \exp(\frac{-Q}{R (800+273)} )$

$\zeta_{800} = C \exp(\frac{-Q}{1073R} )\\\zeta_{800} = 1 \% per hour =0.01\\$

$0.01 = C \exp(\frac{-Q}{1073R} )$ .........................(1)

Creep rate at 700⁰C

$\zeta_{700} = C \exp(\frac{-Q}{R (700+273)} )$

$\zeta_{800} = C \exp(\frac{-Q}{973R} )\\\zeta_{800} = 5.5 * 10^{-2} \% per hour =5.5 * 10^{-4}$

$5.5 * 10^{-4} = C \exp(\frac{-Q}{1073R} )$ .................(2)

Divide equation (1) by equation (2)

$\frac{0.01}{5.5 * 10^{-4} } = \exp[\frac{-Q}{1073R} -\frac{-Q}{973R} ]\\18.182= \exp[\frac{-Q}{1073R} +\frac{Q}{973R} ]\\R = 8.314\\18.182= \exp[\frac{-Q}{1073*8.314} +\frac{Q}{973*8.314} ]\\18.182= \exp[0.0000115 Q]\\$

Take the natural log of both sides

$ln 18.182= 0.0000115Q\\2.9004 = 0.0000115Q\\Q = 2.9004/0.0000115\\Q = 252211.49 J/mol\\Q = 252.2 kJ/mol$

3 0

3 years ago