Ask question

Ask question

All categories

lorasvet [3.4K]

3 years ago

7

The ventilating fan of the bathroom of a building has a volume flow rate of 32 L/s and runs continuously. If the density of air

inside is 1.20 kg/m3, determine the mass of air vented out in one day. The mass of air is kg.

1 answer:

deff fn [24]3 years ago

4 0

Answer:

Nba Youngboy

38 baby 4ktre we put guns to da face who gon die today bkitchk

Explanation:

You might be interested in

Tensile testing provides engineers with the ability to verify and establish material properties related to a specific material.

Sedbober [7]

Answer:

True

Explanation:

Tensile testing which is also referred to as tension testing is a process which materials are subjected to so as to know how well it can be stretched before it reaches breaking point. Hence, the statement in the question is true

7 0

2 years ago

Can someone pls give me the answer to this?

olganol [36]

I think option c 12 is currect

7 0

2 years ago

What is an advantage of using a fully integrated cloud-based data analytics platform?

sweet [91]

Answer:

It gives decision-makers the processing capacity they need to turn raw data into useful knowledge.

Explanation:

Data analysis and the associated cycles (data integration, aggregation, hoarding, and revealing) are totally or partially directed in the cloud with cloud analytics.

3 0

2 years ago

A keyboard, monitor and mouse are all considered as computer hardware and a program is known as a software.

Iteru [2.4K]

Answer:

This should be true because program is a software and mouse and keyboard are specific computer hardware to make your exsperience with a computer more efficent and faster.

5 0

2 years ago

A cylindrical specimen of some metal alloy having an elastic modulus of 108 GPa and an original cross-sectional diameter of 4.5

IgorC [24]

Answer:

The maximum length of the specimen before the deformation was 358 mm or 0.358 m.

Explanation:

The specific deformation ε for the material is:

$\epsilon = \deltaL /L$ (1)

Where δL and L represent the elongation and initial length respectively. From the HOOK's law we also now that for a linear deformation, the deformation and the normal stress applied relation can be written as:

$\sigma = E/ \epsilon$ (2)

Where E represents the elasticity modulus. By combining equations (1) and (2) in the following form:

$L= \delta L/ \epsilon$

$\epsilon =\sigma /E$

So by calculating ε then will be possible to find L. The normal stress σ is computing with the applied force F and the cross-sectional area A:

$\sigma=F/A$

$\sigma=\frac{F} {\pi*d^2/4}$

$\sigma=\frac{2170 N}{\pi*4.5 mm^2/4}$

$\sigma= 136000000 Pa= 136 Mpa$

Then de specific defotmation:

$\epsilon =136 MPa / 108 GPa = 1.26*10^{-3}$

Finally the maximum specimen lenght for a elongation 0f 0.45 mm is:

$L= 0.45 mm/ 1.26*10^{-3} = 358 mm = 0.358 m$

4 0

2 years ago