A factory has 1200 workers of which 720 are male and the rast are female what percent of workers are female
1 answer:
Answer:
Percent of Female Workers = 40%
Explanation:
The percentage of the female workers in the given group of workers can be easily found by the following formula:
where,
Total No. of Workers = 1200
No. of Female Workers = Total Workers - No. of Male Workers
No. of Female Workers = 1200 - 720 = 480
Therefore,
<u>Percent of Female Workers = 40%</u>
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Answer:
Explanation:
First of all, let's remind that:
- The kinetic energy of an object is given by , where m is the mass and v is the speed
- The momentum of an object is given by
- The inertia of an object is proportional to its mass, so we can write , where k just indicates a constant of proportionality
In this problem, we have:
- (the two objects have same kinetic energy)
- (A has three times the momentum of B)
Re-writing both equation we have:
If we divide first equation by second one we get
And if we substitute it into the first equation we get
So, B has 9 times more mass than A, and so B has 9 times more inertia than A, and their ratio is:
The electric field produced by a single-point charge is given by
where
k is the Coulomb's constant
q is the charge
r is the distance from the charge
To find the electric field at x=0.200 m, we need to find the electric field produced by each charge at that point, and then find their resultant.
1) The first charge is , and it is located at x=0, so its distance from the point x=0.200 m is
Therefore, the electric field is
And since the charge is negative, the direction of the field is toward the charge, so toward negative x direction.
2) The second charge is and it is located at x=0.800 m, so its distance from the point is
Therefore, the electric field is
And since the charge is negative, the direction of the field is toward the charge, so toward positive x-direction.
3) The total electric field at x=0.200 m will be given by the difference between the two fields (because they are in opposite directions). Taking the x-positive direction as positive direction, we have
and the sign tells us that the field is directed toward negative x-direction.