<h3>
Answer:</h3>
126.14 g
<h3>
Explanation:</h3>
- Complete combustion of hydrocarbons yields water and carbon dioxide.
- Methane is a hydrocarbon in the homologous series known as alkanes.
- Methane undergoes combustion in air to produce water and carbon dioxide according to the equation below.
CH₄ (g) + 2O₂ (g) → CO₂(g) + 2H₂O(g)
<u>We are given;</u>
We are required to determine the mass of H₂O produced
<h3>Step 1: Moles of H₂O produced</h3>
- From the equation 1 mole of methane undergoes combustion to produce 2 mole of H₂O.
Therefore, Moles of methane = Moles of H₂O × 2
Hence, Moles of H₂O = 7.0 moles
<h3>Step 2: Mass of H₂O produced </h3>
We know that; mass = Moles × Molar mass
Molar mass of water = 18.02 g/mol
Therefore;
Mass of water = 7.0 moles × 18.02 g/mol
= 126.14 g
Thus, the mass of water produced is 126.14 g
1. Different ideas from different scientists (such as schleiden and schwann)
2. B. Describe and examine cells
3. Sorry i don't remember this
hope this helps :)
Molar mads of C2H5OH:
12*2+1*5+16+1
24+5+17
46
no of moles = mass in grams/molar mass
3.4=m/46
3.4*46=m
m=156.4
m=156g
Holds the particles tightly
Answer: pH = 7.36. The pKa of H2PO4− is 7.21.
Explanation:
