In that case, there are three possible scenarios:
-- If the braking force is less than the force delivered by the engine,
then the car will continue to accelerate, and the brakes will eventually
overheat and erupt in flame.
-- If the braking force is exactly equal to the force delivered by the engine,
then the car will continue moving at a constant speed, and the brakes will
eventually overheat and erupt in flame.
-- If the braking force is greater than the force delivered by the engine,
then the car will slow down and eventually stop. If it stops soon enough,
then the absorption of kinetic energy by the brakes will end before the
brakes overheat and erupt in flame. Even if the engine is still delivering
force, the brakes can be kept locked in order to keep the car stopped ...
They do not absorb and dissipate any energy when the car is motionless.
The shadow forms on the first surface away from the shuttle in the direction opposite the sun.
Answer:
option 'b' and 'c'
Explanation:
when we throw ball in upward direction.
acceleration on the body will never be zero because there will always be acceleration due to gravity i.e. 'g' will be acting on it.
and force of 'mg' will also be acting on the body, where m is the mass of the body.
so,
at the top the parameters which will be zero will be velocity and speed.
at the top most point the ball will change it's direction for that velocity will have to be zero at that point.
Answer:
d=117.2845834m
Explanation:
Let's start out with the vertical components
vi=0, vf=?, a=9.8, x=120, t=?
Let's find how long the rock was falling.
x=vi*t+.5*a*t^2
120=0+.5*9.8*t^2
120=4.9*t^2
t=4.9487166s
Since we know the horizontal velocity is constant, we use the formula v=d/t
23.7=d/4.9487166
d=117.2845834m
