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2 years ago

Which is not an example of unbalanced force acting on an object

Physics

1 answer:

Viktor [21]2 years ago

4 0

Answer:

A motorcycle changing speed from 20km/h to 35km/h

Explanation:

it doesn't show unbalanced force acting on the object but instead, the motorcycle changing speed from 20km/h to 35km/h

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A ball thrown straight up takes 1.89s to reach a height of 41.6m.

yulyashka [42]

Answer:

Explanation:

average velocity is 41.6/1.89 = 22.0 m/s

initial velocity u is

22.0 = (u + u - 9.81(1.89))/2

44.0 = 2u - 18.5

62.56 = 2u

u = 31.3 m/s

max height is

v² = u² + 2as

s = (v² - u²) / 2a

s = (0² - 31.3²) / (2(-9.81)) = 49.9 m

49.9 = 41.6 = 8.27 m higher

In process numbers have been rounded to 3 s.d. for reporting purposes.

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2 years ago

Which BEST describes the speed and velocity of the graph?

Neko [114]

I think the answer is A (sorry if it isn't).

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3 years ago

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Which moon has a thick atmosphere made mostly of nitrogen?

Delicious77 [7]

the answer is Titan
explanation: titan fascinates scientists because of its thick atmosphere — which is mostly made of nitrogen gas

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2 years ago

Which is the correct formula for sulfur dichloride

xz_007 [3.2K]

The formula for sulfur dichloride is SCl2

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2 years ago

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A 12.0N force with a fixed orientation does work on a

kvasek [131]

Answer:

(a) $\theta=62.31^{\circ}$

(b) $\theta=117.68^{\circ}$

Explanation:

It is given that,

Force acting on the particle, F = 12 N

Displacement of the particle, $d=(2.00i -4.00j+3.00k)\ m$

Magnitude of displacement, $d=\sqrt{2^2+4^2+3^2}= 5.38\ m$

(a) If the change in the kinetic energy of the particle is +30 J. The work done by the particle is given by :

$W=Fd\ cos\theta$

$\theta$ is the angle between force and the displacement

According to work energy theorem, the charge in kinetic energy of the particle is equal to the work done.

So,

$cos\theta=\dfrac{W}{Fd}$

$cos\theta=\dfrac{+30\ J}{12\times 5.38}$

$\theta=62.31^{\circ}$

(b) If the change in the kinetic energy of the particle is (-30) J. The work done by the particle is given by :

$cos\theta=\dfrac{W}{Fd}$

$cos\theta=\dfrac{-30\ J}{12\times 5.38}$

$\theta=117.68^{\circ}$

Hence, this is the required solution.

8 0

3 years ago