Answer: -39.2 m/s or 39.2 m/s directed downwards
Explanation:
This situation is a good example of Free Fall, where the main condition is that the initial velocity must be zero 
, and the acceleration is constant (acceleration due gravity).
So, in order to calculate the final velocity 
of the rock just at the moment it hitsthe bottom of the cliff, we will use the following equation:
Where:
is the acceleration due gravity (directed downwards)
is the time it takes to the rock to fall down the cliff
This is the rock's final velocity and its negative sign indicates it is directed downwards
Its A according to Ed Genuity
Answer:
3234.2 W
Explanation:
Since intensity I = Power/Area. The intensity of the light from the sun, I = power radiated by sun/area of sphere of radius, r = 1.5 × 10¹¹ m.
So, I = 3.9 10²⁶W/4π(1.5 × 10¹¹ m)² = 2.069 × 10³ W/m².
Now, the power radiated on the patch of area 0.570 m² at the equator is
P = Icos27/A = 2.069 × 10³ W/m² cos27/0.570 m² = 1843.49/0.570 = 3234.2 W
Vf = vi + at
0m/s = 40m/s + a(0.025s)
a = -1600m/s^2
Fnet = ma
Fnet = (0.10kg)(-1600m/s^2)
Fnet = -160 N
hope that helps
Answer:
first order date and most recent order date
Explanation:
it was switched. column 5 should be most recent order date because it's 2020 while column 6 should be first order date because it was in 2019
