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Alexeev081 [22]
3 years ago
6

Which is not an example of unbalanced force acting on an object

Physics
1 answer:
Viktor [21]3 years ago
4 0

Answer:

A motorcycle changing speed from 20km/h to 35km/h

Explanation:

it doesn't show unbalanced force acting on the object but instead, the motorcycle changing speed from 20km/h to 35km/h

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Student A walks up a 10 meter staircase. Student B runs up the same staircase in less
ra1l [238]

Answer: student b ran up the stairs faster

Explanation:if they were going up the same stair case and student b got up there faster that means he was running therefore student b was using more power

6 0
3 years ago
How does the distance traveled by the coin compare to its displacement after ten flips?
Nataliya [291]

Answer:

The positive velocity occurs the instant the coin leaves our hand. It immediately begins slowing up until its upward velocity becomes zero at the maximum height.

Explanation:

hope helps ohjieun and jannatparia

3 0
3 years ago
A 2000 kg car moving at 100 km/h crosses the top of a hill with a radius of curvature of 100 m. What is the normal force exerted
Tpy6a [65]

Answer:

The normal force the seat exerted on the driver is 125 N.

Explanation:

Given;

mass of the car, m = 2000 kg

speed of the car, u = 100 km/h = 27.78 m/s

radius of curvature of the hill, r = 100 m

mass of the driver, = 60 kg

The centripetal force of the driver at top of the hill is given as;

F_c = F_g - F_N

where;

Fc is the centripetal force

F_g is downward force due to weight of the driver

F_N is upward or normal force on the drive

F_N = F_g-F_c\\\\F_N = mg - \frac{mv^2}{r} \\\\F_N = (60 \times 9.8) -\frac{60 \ \times \ 27.78^2 \ }{100} \\\\F_N = 588 \ N - 463 \ N\\\\F_N = 125 \ N

Therefore, the normal force the seat exerted on the driver is 125 N.

6 0
3 years ago
When should you use a piece of pipe as a leverage extension on the handle on a wrench?
Vesnalui [34]

Answer:

D

Explanation:

We must never use a piece of pipe as a leverage extension on the handle on a wrench.

Hence option d is correct.

7 0
3 years ago
I need help pleaseee
Ludmilka [50]

Answer:

8) 709.8875 J

9) The object is at 7.24375 m from the ground

10) Kinetic energy increases as the object falls.

Explanation:

We use the expression for the displacement h(t) as a function of time of an object experiencing free fall:

h(t) = hi - (g/2) t^2

hi being the initial position of the object (10m) above ground, g the acceleration of gravity (9.8 m/s^2), and t the time (in our case 0.75 seconds):

h(0.75) = 10 - 4/9 (0.75)^2 = 7.24375 m

This is the position of the 10 kg object after 0.75 seconds (answer for part 9)

Knowing this position we can calculate the potential energy of the object when it is at this height, using the formula:

U = m g h = 10kg * 9.8 (m/s^2) * 7.24375 m = 709.8875 J (answer for part 8)

Part 10)

the kinetic energy of the object increases as it gets closer to ground, since its velocity is increasing in magnitude because is being accelerated in its motion downwards.

3 0
3 years ago
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