Answer:
im not really good at explaining, but i found this website url:
https://www.numerade.com/questions/a-cyclist-travels-from-point-a-to-point-b-in-10-min-during-the-first-20-min-of-her-trip-she-maintain/
same question just with the explanation
Answer:
D.400 watt
Explanation:
- B/c <em>Pave</em><em>=</em><em>Irms</em><em>Vrms</em>
- <em>Pave</em><em>=</em><em>(</em><em>5</em><em>)</em><em>(</em><em>8</em><em>0</em><em>)</em>
- <em>Pave</em><em>=</em><em>4</em><em>0</em><em>0</em><em> </em><em>watt</em>
<em>where</em><em> </em><em>Pave</em><em> </em><em>=</em><em> </em><em>average</em><em> </em><em>power</em><em> </em>
<em>Irms</em><em>=</em><em>RMS</em><em> </em><em>current</em><em> </em><em>&</em>
<em>Vrms</em><em>=</em><em>RMS</em><em> </em><em>voltage</em>
The temperature of the oxygen gas is 243.75 K.
Using ideal gas law to explain the answer, the absolute temperature of the gas will decrease if the number of moles of the gas increases and it will increase if the volume and/or pressure of the gas increases.
The reaction of the given elements;
volume of the collected oxygen gas, V = 10 L
pressure of the gas, P = 1 atm
number of moles of the gas, n = 0.5
Using ideal law the temperature of the oxygen gas is calculated as follows;
Thus, the temperature of the gas is 243.75 K.
Using ideal gas law to explain the answer. The absolute temperature of the oxygen gas is directly proportional to the product of its pressure and volume and inversely proportional to its number of moles. That is the absolute temperature of the gas will decrease if the number of moles of the gas increases and it will increase if the volume and/or pressure increases.
Learn more here: brainly.com/question/16617695
The answer is c and my reason is I have straight As
Answer:
if you need an actual number answer you can use :Vf = Vi + at. If you throw the ball it will have an initial force beside gravity accelerating the fall temporarily from greater than throw it downwards, its acceleration (in the absence of air resistance) will be greater than 9.8 m/s2 until it slows back down to a constant 9.8 m/s2 after ( t )amount of time
Explanation:
If you drop a ball, it accelerates downward at 9.8 m/s2. if instead you throw the ball straight downwards While throwing, we apply an additional force other than the gravitational force.
This gives an additional, temporary acceleration along with the gravitational acceleration.
Thus from the instant it is thrown and the instant it leaves your hand, the object is under variable acceleration, the variation of acceleration being the reason of the varying force which we do apply on the object. But once it leaves our hand it is always under constant acceleration of g which is9.8 m/s2