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OlgaM077 [116]
3 years ago
9

Why is it harder to remove an electron from fluorine than from carbon?

Chemistry
1 answer:
tatuchka [14]3 years ago
6 0
<span>The valence electrons of both fluorine and carbon are found at about the same distance from their respective nuclei but the greater positive charge of the fluorine nucleus attracts its valence electrons more strongly. </span>
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How many moles of Al are necessary to form 23.6 g of AlBr₃ from this reaction: 2 Al(s) + 3 Br₂(l) → 2 AlBr₃(s) ?
Gnoma [55]

Answer:

0.088 mole of Al.

Explanation:

First, we shall determine the number of mole in 23.6 g of AlBr₃.

This is illustrated below:

Mass of AlBr₃ = 23.6 g

Molar Mass of AlBr₃ = 27 + 3(80) = 267 g/mol

Mole of AlBr₃ =.?

Mole = mass/Molar mass

Mole of AlBr₃ = 23.6 / 267

Mole of AlBr₃ = 0.088 mol

Next, we shall writing the balanced equation for the reaction.

This is given below:

2Al(s) + 3Br₂(l) → 2AlBr₃(s)

From the balanced equation above,

2 moles of Al reacted with 3 mole of Br₂ to 2 moles AlBr₃.

Finally, we shall determine the number of mole of Al needed for the reaction as follow:

From the balanced equation above,

2 moles of Al reacted to 2 moles AlBr₃.

Therefore, 0.088 mole of Al will also react to produce 0.088 mole of AlBr₃.

4 0
3 years ago
Nitrogen in plants and soil is changed into nitrogen compounds by _____.
grandymaker [24]

Answer:

A

Explanation:

because It's the process by which atmospheric nitrogen is converted either by a natural or an industrial means to form of nitrogen such as ammonia.

5 0
2 years ago
He chemical formula for lithium hydride is LiH A chemist determined by measurements that 0.0800 moles of lithium hydride partici
sweet-ann [11.9K]

Answer:

Mark me brainlist I will then answer in comment

3 0
3 years ago
Currently, radioactive waste is:
kaheart [24]
The answer is B....Brainliest?....
6 0
3 years ago
Read 2 more answers
Given that you added about 5ug of purified acid phosphatase to tube A, calculate the amount of acid phosphatase that was present
Reil [10]

Hey there!:

Amount of purified acid phosphatase added to tube A = 5 ug ( micrograms )

Amount of acid phosphatase present in 400 ug of wheat germ extract  in tube B :

1 / 100 = 5x / 400 =

100 x = ( 0.5 ) ( 400 ) =

x = (0.5 ) ( 400 ) = 100

x = 200 / 100

x =  2 ug


The amount of acid phosphatase present in 400 ug of the  wheat germ in tube B is 2 ug


Hope that helps!

6 0
3 years ago
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