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myrzilka [38]
3 years ago
6

1) A substance has a half life of 20 years. what percentage would be left after 40 years?

Physics
1 answer:
Umnica [9.8K]3 years ago
5 0
1) The half-life is the time required for a substance to reduce to half its initial value. In formulas:
\frac{m(t)}{m_0}  = ( \frac{1}{2} )^{t/t_{1/2}} (1)
where
m(t) is the amount of substance left at time t
m0 is the initial mass
t_{1/2} is the half-life

In this problem, the half-life of the substance is 20 years:
t_{1/2} = 20 y
therefore, the fraction of sample left after t=40 years will be
\frac{m(t)}{m_0}=( \frac{1}{2})^ \frac{40 y}{20 y}  = ( \frac{1}{2})^2 =  \frac{1}{4}

So, only 1/4 of the original sample will be left, which corresponds to 25%.

2) We can use again formula (1), by re-arranging it:
m_0 =  \frac{m(t)} {( \frac{1}{2} )^{ \frac{t}{t_{1/2} }}}
If we use m(t)=10 g (mass of uranium left at time t), and t=4 t_{1/2} (the time is equal to 4 half lifes), we get
m_0 =  \frac{10 g}{ (\frac{1}{2})^4 } =16 \cdot 10 g = 160 g
So, the initial sample of uranium was 160 g.
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uppose a wheel is initially rotating at 10.0 rad/s while undergoing constant angular acceleration reaching a speed of 30.0 rad/s
Paul [167]

Answer:

t = 22.2 s

Explanation:

angular distance covered in the 36.0 s is

θ = ω(avg)t = ½(10.0 + 30.0)36 = 720 radians

720/2 = 360 radians

α = Δω/t = (30 - 10)/36 = 5/9 rad/s²

θ = ω₀t + ½αt²

360 = 10.0t + ½(5/9)t²

   0 = (5/18)t² + 10.0t - 360

   0 = t² + 36t - 1296

t = (-36 ±√(36² - 4(1)(-1296))) / 2

t = (-36 ±√(6480)) / 2

t = -18 ±√1620

we ignore the negative time result as it occurs before we care.

t = -18 + √1620 = 22.249223... s

8 0
3 years ago
The tension of a guitar string is increased by 40%. By what factor odes the fundamental frequency of vibration change? a. 1.13 b
bogdanovich [222]

Answer:

<h3> b. 1.18</h3>

Explanation:

The fundamental frequency in string is expressed as;

F1 = 1/2L√T/m .... 1

L is the length of the string

T is the tension

m is the mass per unit length

If the tension is increased by 40%, the new tension will be;

T2 = T + 40%T

T2 = T + 0.4T

T2 = 1.4T

The new fundamental frequency will be;

F2 = 1/2L√1.4T/m ..... 2

Divide 1 by 2;

F2/F = (1/2L√1.4T/m)/1/2L√T/m)+

F2/F = √1.4T/m ÷ √T/m

F2/F = √1.4T/√m ×√m/√T

F2/F = √1.4T/√T

F2/F = 1.18√T/√T

F2/F = 1.18

F2 = 1.18F

Hence the fundamental frequency of vibration changes by a factor of 1.18

8 0
3 years ago
A load of 1 kW takes a current of 5 A from a 230 V supply. Calculate the power factor.
Pachacha [2.7K]

Answer:

Power factor = 0.87 (Approx)

Explanation:

Given:

Load = 1 Kw = 1000 watt

Current (I) = 5 A

Supply (V) = 230 V

Find:

Power factor.

Computation:

Power factor = watts / (V)(I)

Power factor = 1,000 / (230)(5)

Power factor = 1,000 / (1,150)

Power factor = 0.8695

Power factor = 0.87 (Approx)

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Answer:

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