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tigry1 [53]
4 years ago
10

In Universe , recently discovered by an intrepid team of chemists who also happen to have studied interdimensional travel, quant

um mechanics works just as it does in our universe, except that there are seven orbitals instead of the usual number we observe here. Use these facts to write the ground-state electron configurations of the sixth and seventh elements in the first transition series in Universe . Note: you may use to stand for the electron configuration of the noble gas at the end of the row before the first transition series.
Chemistry
1 answer:
lawyer [7]4 years ago
8 0

Answer:

According to Hund's rule and the Aufbau principle in which the orbitals must be filled with electrons, they are not strictly applied in the real universe, because the intermediate and electron-filled atomic orbitals are very stable . Because there are four d-orbitals in universe L, a typical half-full configuration will be xd4 and its full configuration will be xd8, where x is the primary orbital for any specific element. Here is an example:

Vahadium ₂₃V

in real universe: [Ar]₈ 3d³4s²

in universe L: [Ar]₁₈ 3d⁴4s¹

Chromium

in real universe: [Ar]₈ 3d⁵4s¹

in universe L: [Ar]₁₈ 3d⁴4s²

Explanation:

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<h3>Answer:</h3>

5.00 mol O₂

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
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<u>Chemistry</u>

<u>Atomic Structure</u>

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<u>Step 1: Define</u>

3.01 × 10²⁴ atoms O₂

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

  1. Set up:                              \displaystyle 3.01 \cdot 10^{24} \ atoms \ O_2(\frac{1 \ mol \ O_2}{6.022 \cdot 10^{23} \ atoms \ O_2})
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<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

4.99834 mol O₂ ≈ 5.00 mol O₂

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