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Mazyrski [523]
3 years ago
8

How do you think air resistance affects measured values of g? If you used a ping pong ball, for example, how would this affect t

he fall-time? Would you expect the ping pong ball and the steel ball to land at the same time if they were both dropped from a height of ϭ.ϱm? What would happen if you dropped both balls from a height of ϮϬm?
Physics
1 answer:
valentinak56 [21]3 years ago
3 0

Answer:

A) Air resistance acts in a direction opposite the the fall of an object reducing it by doing work against the weight of the object due to gravity.

B) using a ping pong ball, the time of fall will be greatly reduced since it has little weight (its mass x acceleration due to gravity) against the air resistance. The net downward force of the weight and the air resistance will be small.

C) No, I wouldn't expect them to fall at the same time. The steel ball will have more weight compared to the ping pong ball and hence it will have a larger net force downwards.

D) If they are both released from a 6 m height, the steel ball will fall to the ground first since it has a larger net force downwards.

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An automobile tire is rated to last for 35,000 miles. to an order of magnitude, through how many revolutions will it turn?
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Electric field lines always begin at _______ charges (or at infinity) and end at _______ charges (or at infinity). One could als
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A train has an acceleration of magnitude 0.90 m/s2 while stopping. A pendulum with a 0.55-kg bob is attached to a ceiling of one
anygoal [31]

The angle of the pendulum with the vertical is 5.2^{\circ}

Explanation:

As the train decelerates, the bob of the pendulum will feel a force given by

F=ma

where

m = 0.55 kg is the mass of the bob

a=0.9 m/s^2 is the magnitude of the acceleration

In the horizontal direction.

The pendulum will be inclined at an angle \theta from the vertical, so it will be in equilibrium, and therefore the horizontal component of the tension in the string must be equal to the net force F of the previous equation:

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where T is the tension in the string.

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tan \theta = \frac{a}{g}

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Learn more about forces and acceleration:

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