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hoa [83]
4 years ago
11

You are 12 miles north of your base camp when you begin walking north at a speed of 2 miles per hour. What is your location, rel

ative to your base camp, after walking for 5 hours?
Physics
2 answers:
liubo4ka [24]4 years ago
8 0
If you walk at a pace of 2 miles per hour for 5 hours, you should have walked 10 miles. You would be 2 miles away from your base camp. 
noname [10]4 years ago
4 0

Answer:

22 miles (North)        

Explanation:

Given:

velocity = 2 miles per hour (towards North)

Time taken = 5 hours

Displacement in 5 hours = velocity x time

                                        = ( 2 x 5 ) miles

                                        = 10 miles (North wards)

Initial displacement from the base of the camp = 12 miles (North wards)

Thus, location from the base camp after walking for 5 hours is:

12 miles + 10 miles = 22 miles

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A copper cylinder is initially at 21.1 ∘C . At what temperature will its volume be 0.163 % larger than it is at 21.1 ∘C?
fomenos

To solve this problem we will apply the concepts related to the final volume of a body after undergoing a thermal expansion. To determine the temperature, we will use the given relationship as well as the theoretical value of the volumetric coefficient of thermal expansion of copper. This is, for example to the initial volume defined as V_1, the relation with the final volume as

V_2 = V_1 +0.163\% V_1

V_2 = V_1 +0.00163V_1

V_2 = 1.00163V_1

Initial temperature = 21.1\°C

Let T be the temperature after expanding by the formula of volume expansion

we have,

V_2 = V_1 (1+\gamma \Delta t)

Where \gamma is the volume coefficient of copper 5.1*10^{-5}/C

1.00163V_1 = V_1(1+\gamma(T-21.1\°))

1.00163 = 1+5.1*10^{-5}(T-21.1\°)

0.00163 = 0.000051T-0.0010761

T = 53.0608\°C

Therefore the temperature is 53.06°C

7 0
4 years ago
Can someone please help? Thank u!
Snowcat [4.5K]

Answer:

B. 7.5 m/s^2

Explanation:

To find acceleration you need to subtract the final velocity by the starting velocity then divide that by the time

a= v-v/t

a= 60-0/8

a= 60/8

a=7.5 m/s^2

7 0
3 years ago
The magnetic field in the region between the poles of an electromagnet is uniform at any time, (1 point) but is increasing at th
olga nikolaevna [1]

Answer:

B)

The magnitude of induced emf in the conducting loop is 0.99 mV.

Explanation:

Rate of increase in magnetic field per unit time = 0.090 T/s

Area of the conducting loop = 110 cm^2 = 0.0110 m^2

Electromagnetic induction is the production of an emf or voltage in a coil of wire due to a changing magnetic field through the coil.

Induced e.m.f is given as:

EMF = (-N*change in magnetic field/time)*Area

EMF = rate of change of magnetic field per unit time * Area

EMF = 0.090 * 0.0110

EMF = 0.00099 V

EMF = 0.99 mV

5 0
3 years ago
The horizontal force exerted between the tires of a 500kg car and the ground is 980N. if the car starts from rest, how far will
Maksim231197 [3]

Answer:

Explanation:

d = ½at²

d = ½(F/m)t²

d = ½(980/500)5²

d = 24.5 m

6 0
2 years ago
Dan is 50 years old, is beginning to look back at the successes and failures in his life, and hopes to use this reflection to de
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Answer:

C. Midlife Crisis.

Explanation:

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