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denpristay [2]
3 years ago
8

Calculate the [oh−] in a solution with a ph of 12.52.

Chemistry
1 answer:
BaLLatris [955]3 years ago
6 0
PH + pOH = 14

12.52 + pOH = 14

pOH = 14 - 12.52

pOH = 1.48

[OH⁻] = 10^ -pOH

[OH⁻] = 10 ^- 1.48

[OH⁻] = 0.033 M
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