Answer:
[Acetic acid] = 0.07 M
[Acetate] = 0.13 M
Explanation:
pH of buffer = 5
pKa of acetic acid = 4.76
![pH=p_{Ka} + log\frac{[Salt]}{[Acid]}](https://tex.z-dn.net/?f=pH%3Dp_%7BKa%7D%20%2B%20log%5Cfrac%7B%5BSalt%5D%7D%7B%5BAcid%5D%7D)
Now using Henderson-Hasselbalch equation
![5=4.76 + log\frac{[Acetate]}{[Acetic\;acid]}](https://tex.z-dn.net/?f=5%3D4.76%20%2B%20log%5Cfrac%7B%5BAcetate%5D%7D%7B%5BAcetic%5C%3Bacid%5D%7D)
![log\frac{[Acetate]}{[Acetic\;acid]} = 0.24](https://tex.z-dn.net/?f=log%5Cfrac%7B%5BAcetate%5D%7D%7B%5BAcetic%5C%3Bacid%5D%7D%20%3D%200.24)
![\frac{[Acetate]}{[Acetic\;acid]} = 1.74](https://tex.z-dn.net/?f=%5Cfrac%7B%5BAcetate%5D%7D%7B%5BAcetic%5C%3Bacid%5D%7D%20%3D%201.74)
....... (1)
It is given that,
[Acetate] + [Acetic acid] = 0.2 M ....... (2)
Now solving both the above equations
[Acetate] = 1.74[Acetic acid]
Substitute the concentration of acetate ion in equation (2)
1.74[Acetic acid] + [Acetic acid] = 0.2 M
[Acetic acid] = 0.2/2.74 = 0.07 M
[Acetate] = 0.2 - 0.07 = 0.13 M
Answer:
The Californian red wine (pH 3.5) has a hydrogen concentration of 0.00032M
The italian white wine (pH 2.9) has a hydrogen concentration of 0.00126 M
Explanation:
<u>Step 1:</u> Data given
Wine 1 has a pH of 3.5
Wine 2 has a pH of 2.9
Wine 2 is more acid so should have more hydrogen ions
<u>Step 2:</u> Calculate hydrogen concentration
pH = -log [H+]
Wine 1: pH = 3.5 = -log[H+]
[H] = 10 ^-3.5 M = 0.00032 M
Wine 2: pH =2.9 = -log[H+]
[H+] = 10^-2.9 = 0.00126 M
The Californian red wine (pH 3.5) has a hydrogen concentration of 0.00032M
The italian white wine (pH 2.9) has a hydrogen concentration of 0.00126 M
The italian white wine has a higher concentration of hydrogen ions, what means it's more acid than the californian red wine.
Shielding effect being attendency of the inner electrons to repel the outermost electrons, an increase in shielding effect increases atomic radius and decrease reduces the atomic radius
