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nydimaria [60]
3 years ago
11

Which element in group 16 is most likely to gain an electron?

Chemistry
1 answer:
Jobisdone [24]3 years ago
4 0

oxygen because it has only one oxidation state of -2, all the other elements in the group have multiple oxidation states.

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If 0.2 g of nitrobenzene are added to 10.9 g of naphthalene, calculate the molality of the solution. (given: molar mass of nitro
In-s [12.5K]

Molality is defined as 1 mole of a solute in 1 kg of solvent.  

Molality=

\frac{Number of moles of solute}{Mass of solvent in kg}

Number of moles of solute, n=  

\frac{Given mass of the substance}{Molar mass of the substance}

Given mass of the nitrobenzene=0.2 g

Molar mass of the substance= 123.06 g mol⁻¹

Number of moles of nitrobenzene,  

n= \frac{0.2 }{123.06}

Number of moles of nitrobenzene, n= 0.0016  mol

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Molality= \frac{0.0016}{0.0109 }

Molality= 0.146 m

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Answer:

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Sunny_sXe [5.5K]
Whereas semidiurnal tides are observed at the equator at all times, most locations north or south of the equator experiencetwo unequal high tides and twounequal low tides per tidal day; this is called a mixed tide and the difference in height between successive high (or low) tides iscalled the diurnal inequality.
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Explain why Potassium is more reactive than lithium?​
Elis [28]

Explanation:

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2 years ago
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What mass of solute will dissolve in 100g of water at the following temperatures?
zimovet [89]

KNO_3 at 70°C = 130 gram

NaCl at 100°C= 40 gram

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<h3>What is solubility?</h3>

Solubility is defined as the maximum amount of a substance that will dissolve in a given amount of solvent at a specified temperature.

Amount of a substance (called the solute) that dissolves in a unit volume of a liquid substance (called the solvent) to form a saturated solution under specified conditions of temperature and pressure. Solubility is expressed usually as moles of solute per 100 grams of solvent.

Hence,

KNO_3 at 70°C = 130 gram

NaCl at 100°C= 40 gram

NH₂Cl at 90°C= 70 gram

Learn more about solubility here:

brainly.com/question/14366471

#SPJ1

4 0
1 year ago
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