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Ugo [173]
3 years ago
8

Why is the greenhouse effect important to life on earth

Chemistry
2 answers:
navik [9.2K]3 years ago
8 0

Answer:

Because Greenhouse gases let the sun's light shine onto the Earth's surface, but they trap the heat that reflects back up into the atmosphere. And this way, they act like the glass walls of a greenhouse. This greenhouse effect also keeps the Earth warm enough to sustain life.

Explanation:

Leya [2.2K]3 years ago
8 0

Answer:

greenhouse gases trap heat for the earth so if it was unavaible no heat would be conserved

Explanation:

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Reactants are substances that?
RSB [31]
A substance that undergoes change during a reaction, usually from coming in contact with another substance
4 0
3 years ago
10 moles of carbon dioxide has a mass of 440 g. What is the relative formula mass of carbon dioxide?
Ksenya-84 [330]

Answer: 44g

Explanation: The formular for finding Moles is ;

Moles =  Mass / Molar Mass or Formular Mass.

Base on this question; Moles = 10, Mass = 440g, and Formular Mass = ?

Making 'Formular Mass', subject of the formular; we thus have;

Formular mass = Mass / Moles = 440/ 10 = 44g

7 0
3 years ago
In your own words what is equilibrium?
fenix001 [56]

Answer:

when the forward and reverse reactions occur at equal rates.

chemical reaction is in equilibrium when the concentrations of reactants and products are constant - their ratio does not vary.

8 0
3 years ago
What are the periodic trends of ionic radii? Check all that apply.
Troyanec [42]
Atomic radii increase when going down a group and decreases when going towards the anion periods. So A and D.
6 0
3 years ago
Read 2 more answers
Low concentrations of EDTA near the detection limit gave the following dimensionless instrument readings: 175, 104, 164, 193, 13
Mila [183]

Answer:

Following are the solution to these question:

Explanation:

Calculating the mean:

\bar{x}=\frac{175+104+164+193+131+189+155+133+151+176}{10}\\\\

  =\frac{1571}{10}\\\\=157.1

Calculating the standardn:

\sigma=\sqrt{\frac{\Sigma(x_i-\bar{x})^2}{n-1}}\\\\

Please find the correct equation in the attached file.

=28.195

For point a:

=3s+yblank \\\\=3 \times 28.195+50\\\\=84.585+50\\\\=134.585\\

For point b:

=3 \ \frac{s}{m}\\\\ = \frac{(3 \times 28.195)}{1.75 \times 10^9 \ M^{-1}}\\\\= 4.833 \times 10^{-8} \ M

For point c:

= 10 \frac{s}{m} \\\\= \frac{(10 \times 28.195)}{1.75 x 10^9 \ M^{-1}}\\\\ = 1.611 \times 10^{-7}\  M

It is calculated by using the slope value that is 1.75 \times 10^9 M^{-1}. The slope value 1.75 \times 10^9 M^{-1}is ambiguous.

7 0
2 years ago
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