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3 years ago

11

Propanoic acid (propionic acid) has the formula CH3CH2COOH. Draw the conjugate base, that is, the structure that results from de

protonation. Include all hydrogen atoms and any appropriate formal charges.

1 answer:

devlian [24]3 years ago

7 0

Answer:

Conjugate base: Propionate

Explanation:

Conjugate base contains one less proton as compared to it's parent acid. Deprotonation occurs from most acidic region.

Propionic acid deprotonates to produce it's strong conjugate base propionate.

In propionic acid, -OH group in -COOH functional moiety dissociates to produce $H^{+}$ . Because the O-H bond electrons remains highly polarized towards oxygen atom due to electron withdrawing inductive effect as well as resonating effect of -COOH moiety.

Structure of conjugate base has been shown below.

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The model of a “sea of electrons” helps explain ____.

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Answer:

The correct answer is C.) metallic bonds

Explanation:

Metallic bonds are formed between metal compounds and are very strong. These links are explained by the "sea model of electrons", where valence electrons are ceded by each metal atom, becoming positive ions forming a three-dimensional crystalline network. These electrons move forming a network ("sea") that allows the union of the positive ions formed.

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What is the molality of sodium chloride in solution that is 13.0% by mass sodium chloride and that has a density of 1.10 g/ml?

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Answer is: molality od sodium chloride is 2,55 mol/kg.
V(solution) = 100 ml.
m(solution) = d(solution) · V(solution).
m(solution) = 1,10 g/ml · 100 ml.
m(solution) = 110 g.
ω(NaCl) = 13,0% = 0,13.
m(NaCl) = ω(NaCl) · m(solution).
m(NaCl) = 0,13 · 110 g.
m(NaCl) = 14,3 g.
n(NaCl) = m(NaCl) ÷ M(NaCl).
n(NaCl) = 14,3 g ÷ 58,5 g/mol.
n(NaCl) = 0,244 mol.
m(H₂O) = 110 g - 14,3 g.
m(H₂O) = 95,7 g = 0,0957 kg.
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3 years ago

A swimming-pool worker wants the pool's pH to be 7.2. She comes by to test the water and finds that the pH is 6.2. What should s

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3 years ago

A 0.245-L flask contains 0.467 mol co2 at 159 °c. Calculate the pressure using the ideal gas law.

lubasha [3.4K]

Answer:

Pressure, P = 67.57 atm

Explanation:

<u>Given the following data;</u>

Volume = 0.245 L
Number of moles = 0.467 moles
Temperature = 159°C
Ideal gas constant, R = 0.08206 L·atm/mol·K

<u>Conversion:</u>

We would convert the value of the temperature in Celsius to Kelvin.

T = 273 + °C

T = 273 + 159

T = 432 Kelvin

To find the pressure of the gas, we would use the ideal gas law;

PV = nRT

Where;

P is the pressure.
V is the volume.
n is the number of moles of substance.
R is the ideal gas constant.
T is the temperature.

Making P the subject of formula, we have;

$P = \frac {nRT}{V}$

Substituting into the formula, we have;

$P = \frac {0.467*0.08206*432}{0.245}$

$P = \frac {16.5551}{0.245}$

<em>Pressure, P = 67.57 atm</em>

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3 years ago