Propanoic acid (propionic acid) has the formula CH3CH2COOH. Draw the conjugate base, that is, the structure that results from de
protonation. Include all hydrogen atoms and any appropriate formal charges.
1 answer:
Answer:
Conjugate base: Propionate
Explanation:
- Conjugate base contains one less proton as compared to it's parent acid. Deprotonation occurs from most acidic region.
- Propionic acid deprotonates to produce it's strong conjugate base propionate.
- In propionic acid, -OH group in -COOH functional moiety dissociates to produce
. Because the O-H bond electrons remains highly polarized towards oxygen atom due to electron withdrawing inductive effect as well as resonating effect of -COOH moiety.
- Structure of conjugate base has been shown below.
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Answer:
0.08kg
Explanation:
Given parameters:
Temperature of water = 100°C
Quantity of heat released = 180414.08J
Unknown:
Quantity of water condensed = ?
Solution:
This is simple phase change process without any attendant change in temperature.
To solve this problem, use the formula below;
H = mL
H is the heat released
m is mass
L is the latent heat of condensation of water = 2260 kJ/kg
Insert the parameters and solve;
180,414.08 = m x 22.6 x 10⁵ J/kg
m = = 0.08kg