Answer:
2-methyl-2-butanol and 2-ethoxy-2-methylbutane
Explanation:
When the elimination occurs, a good leaving group must leave the compound and will be replaced. A good leaving group is a nucleophile, which intends to bond with compounds with positive charges. In this case, the bromine and iodine ions are nucleophiles that will leave the compounds.
In the mixture ethanol and water, two compounds must replace the leaving groups, which are strong nucleophiles: OH⁻ and ⁻OCH₂CH₃ (O is a strong nucleophile, and after the bonding, H⁺ will be lost in the ethanol molecule).
So, the two possible products are 2-methyl-2-butanol and 2-ethoxy-2-methylbutane, as shown below.
Answer:
A. Metallic Bonds
Explanation:
Metallic bonding is a type of chemical bonding that arises from the electrostatic attractive force between conduction electrons and positively charged metal ions.
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Molecular weight of (NH4)2 CO3 = 96 gm. 96 gm (NH4)2CO3 = 1 mol of (NH4)2CO3 = 2 moles of NH4.
Therefore 1.3 gm of (NH4)2CO3 = 1.3x2/ 96 = 0.027 moles.
B.
There is no covalent bonds in pure H2O. Only hydrogen