Propanoic acid (propionic acid) has the formula CH3CH2COOH. Draw the conjugate base, that is, the structure that results from de
protonation. Include all hydrogen atoms and any appropriate formal charges.
1 answer:
Answer:
Conjugate base: Propionate
Explanation:
- Conjugate base contains one less proton as compared to it's parent acid. Deprotonation occurs from most acidic region.
- Propionic acid deprotonates to produce it's strong conjugate base propionate.
- In propionic acid, -OH group in -COOH functional moiety dissociates to produce
. Because the O-H bond electrons remains highly polarized towards oxygen atom due to electron withdrawing inductive effect as well as resonating effect of -COOH moiety.
- Structure of conjugate base has been shown below.
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<h3>Answer:</h3>
0.819 mol Ag
<h3>General Formulas and Concepts:</h3><u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
- Left to Right<u> </u>
<u>Chemistry</u>
<u>Atomic Structure</u>
- Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
<u>Stoichiometry</u>
- Using Dimensional Analysis
<u>Step 1: Define</u>
4.93 × 10²³ atoms Ag
<u>Step 2: Identify Conversions</u>
Avogadro's Number
<u>Step 3: Convert</u>
- Set up:
- Divide:
<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 3 sig figs.</em>
0.818665 mol Ag ≈ 0.819 mol Ag