Answer:
=> 2.8554 g/mL
Explanation:
To determine the formula to use in solving such a problem, you have to consider what you have been given.
We have;
mass (m) = 16.59 g
Volume (v) = 5.81 mL
From our question, we are to determine the density (rho) of the rock.
The formula:
Substitute the values into the formula:
= 2.8554 g/mL
Therefore, the density (rho) of the rock is 2.8554 g/mL.
Answer:
3.636 grams of sodium bicarbonate is required.
Explanation:
Using ideal gas equation:
PV = nRT
where,
P = Pressure of gas = 753.5 mmHg = 0.9914 atm
()
V = Volume of gas = 1.08 L
n = number of moles of gas = ?
R = Gas constant = 0.0821 L.atm/mol.K
T = Temperature of gas = 24.5 °C= 297.65 K
Putting values in above equation, we get:
Percentage recovery of carbon dioxide gas = 49.4%
Actual moles of carbon dioxide formed: 49.4% of 0.0438 mole
According to reaction ,1 mol is obtained from 2 moles of sodium bicarbonate.
Then 0.02164 moles f carbon dioxide will be obtained from:
Mass of 0.04328 moles pf sodium bicarbonate:
0.04328 mol × 84 g/mol = 3.636 g
3.636 grams of sodium bicarbonate is required.
