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guapka [62]
3 years ago
13

[40 Points]

Chemistry
1 answer:
pashok25 [27]3 years ago
8 0

the one that is wrong is a. increase the molecular weight of the gas , the molecular weight never changes when a solid turns to a liquid or when a liquid turns to a gas .

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What do you call a circuit with only one path
DanielleElmas [232]
If I'm correct the answer should be a series circuit :) Hopefully this helps you out
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3 years ago
Calculate the number of grams contained in each of the following number of moles. Report your answer with the appropriate number
Debora [2.8K]

<u>Answers:</u>

a. 131.85 grams

b. 134.69 grams

To calculate the number of grams in the number of moles given for each compound, consider the formula:

<em>Moles = No. of grams / molar mass</em>

Therefore, to find the gram it will become:

<em>No. of grams = moles x molar mass</em>

a.  0.410 mol of NaCl (sodium chloride)

Molar mass of NaCl = (286.14 + 35.45) = 321.59

No. of grams = moles x molar mass

No. of grams = 0.410 x 321.59 = 131.85 grams

b. 4.80 mol of C2H4 (ethylene)

Molar mass of C2H4 = (12.01 x 2) + (1.01 x 4) = 28.06

No. of grams = moles x molar mass

No. of grams = 4.80 x 28.06 = 134.69 grams

3 0
3 years ago
Read 2 more answers
Which statements describe the law of conservation of charge? Check all that apply.
AlekseyPX
The statements in accordance with the law of conservation of charge are:
A. The total charge of the reactants and products must be equal
B. The net charge of an isolated system remains constant

Both of these statements follow the law of conservation of charge which states that charge may neither be created nor destroyed, due to which the total charge in an isolated system (one in which charge can not move in or out of) remains constant.
5 0
3 years ago
In the molecules below, areas that have a partial negative charge are pink and areas that have a partial positive charge are blu
Kaylis [27]

Answer:

Dipole-dipole interactions

Step-by-step explanation:

Each molecule consists of <em>two different elements</em>.

Thus, each molecule has permanent <em>bond dipoles</em>.

The dipoles do not cancel, so the attractive forces are dipole-dipole attractions.

"Covalent bonds" is <em>wrong,</em> because there are no bonds between the two molecules.

There are dipole-induced dipole and London dispersion forces, but they are much weaker than the dipole-dipole attractions.

4 0
3 years ago
Using standard free energy of formation values given in the introduction, calculate the equilibrium constant kp of the reaction
WINSTONCH [101]

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= 2 * 66.08 - 2 * 87.6 = -43.04 kJ /mol

dG = - 2.303 RT log K

-43.04 = - 2.303 RT log K

7.54 = log K

K = 3.42 * 10^7

Kp = k (RT)^dn

d n = 2 - 1 -2 = -1

Kp = (3.42 * 10^7) (8.314 * 298)^-1

Kp = 1.31 * 10^4

6 0
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