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n200080 [17]
4 years ago
13

Which statement is most likely correct?

Physics
2 answers:
DENIUS [597]4 years ago
8 0

Answer:

the correct answer is B

Valentin [98]4 years ago
5 0

Answer:

It is D my beautiful children <3

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A metal cube with sides of length a=1cm is moving at velocity v0→=1m/sj^ across a uniform magnetic field B0→=5Tk^. The cube is o
Nitella [24]

Answer:

the magnitude of the electric field is 1.25 N/C

Explanation:

The induced emf in the cube ε = LB.v where B = magnitude of electric field = 5 T , L = length of side of cube = 1 cm = 0.01 m and v = velocity of cube = 1 m/s

ε = LB.v = 0.01 m × 5 T × 1 m/s = 0.05 V

Also, induced emf in the cube ε = ∫E.ds around the loop of the cube where E = electric field in metal cube

ε = ∫E.ds

ε = Eds since E is always parallel to the side of the cube

= E∫ds  ∫ds = 4L since we have 4 sides

= E(4L)

= 4EL

So,4EL = 0.05 V

E = 0.05 V/4L

= 0.05 V/(4 × 0.01 m)

= 0.05 V/0.04 m

= 1.25 V/m

= 1.25 N/C

So, the magnitude of the electric field is 1.25 N/C

7 0
3 years ago
4.72 A full-wave bridge-rectifier circuit with a 1-k load operates from a 120-V (rms) 60-Hz household supply through a 12-to-1 s
melisa1 [442]

Answer:

a) 12.74 V

b) Two pairs of diode will work only half of the cycle

c) 8.11 V

d) 8.11 mA

Explanation:

The voltage after the transformer is relationated with the transformer relationshinp:

V_o=Vrms*\frac{1}{12}\\V_o=10Vrms

the peak voltage before the bridge rectifier is given by:

V_{op}=Vo*\sqrt{2}\\V_{op}=14.14V

The diodes drop 0.7v, when we use a bridge rectifier only two diodes are working when the signal is positive and the other two when it's negative, so the peak voltage of the load is:

V_l=V_{op}-2(0.7)\\V_l=12.74V

As we said before only two diodes will work at a time, because the signal is half positive and half negative,so two of them will work only half of the cycle.

The averague voltage on a full wave rectifier is given by:

V_{avg}=2*\frac{V_l}{\pi}\\V_{avg}=8.11V

Using Ohm's law:

I_{avg}=\frac{V_{avg}}{R}\\\\I_{avg}=8.11mA

7 0
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