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4 years ago

Which statement is most likely correct?

Physics

2 answers:

DENIUS [597]4 years ago

8 0

Answer:

the correct answer is B

Valentin [98]4 years ago

5 0

Answer:

It is D my beautiful children <3

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8.0kg rocket fired horizontally encounters a force of air resistance of 4.9 N. The force supplied by the rocket's engine is 60.9

Gelneren [198K]

60.9 - 4.9= 56
56 is the net force
using the formula F = ma
56= 8a
a = 7
acceleration is 7ms^-2

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3 years ago

Which combination of cell increases both electric current and electromotive force?

inn [45]

Answer:

In parallel combination, the cells are connected in such a way that the potential difference of the circuit is same as the cells used in the circuit but the time of current flowing increases

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1 year ago

The process of circular motion in the Earth’s mantle that causes the plates of the lithosphere to move is called

diamong [38]

Convection moves in a cicular motion

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4 years ago

Read 2 more answers

If a proton and an electron are released when they are 6.50×10⁻¹⁰ m apart (typical atomic distances), find the initial accelerat

Cerrena [4.2K]

Answer:

(a) Acceleration of electron= 5.993×10²⁰ m/s²

(b) Acceleration of proton= 3.264×10¹⁷ m/s²

Explanation:

Given Data

distance r= 6.50×10⁻¹⁰ m

Mass of electron Me=9.109×10⁻³¹ kg

Mass of proton Mp=1.673×10⁻²⁷ kg

Charge of electron qe= -e = -1.602×10⁻¹⁹C

Charge of electron qp= e = 1.602×10⁻¹⁹C

To find

(a) Acceleration of electron

(b) Acceleration of proton

Solution

Since the charges are opposite the Coulomb Force is attractive

$F=\frac{1}{4(\pi)Eo }\frac{|qp*qe|}{r^{2} }\\ F=(8.988*10^{9}Nm^{2}/C^{2})*\frac{(1.602*10^{-19})^{2} }{(6.50*10^{-10} )^{2} } \\F=5.46*10^{-10}N$

From Newtons Second Law of motion

F=ma

a=F/m

For (a) Acceleration of electron

$a=F/Me\\a=(5.46*10^{-10} )/9.109*10^{-31}\\ a=5.993*10^{20}m/s^{2}$

For(b) Acceleration of proton

$a=F/Mp\\a=(5.46*10^{-10} )/1.673*10^{-27} \\a=3.264*10^{17}m/s^{2}$

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3 years ago

Light and radio waves travel through a vacuum in a straight line at a speed of very nearly 3.00 ´ 108 m/s. How far is light year

mezya [45]

<span>We need to calculate the number of seconds in one year. time = (365 days) (24 hours/day) (3600 seconds/hour) time = 31536000 seconds We can calculate the distance that light travels in this many seconds. distance = speed x time distance = (3.00 x 10^8 m/s) (31536000 seconds) distance = 9.46 x 10^{15} meters A light year is 9.46 x 10^{15} meters</span>

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3 years ago