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n200080 [17]
4 years ago
13

Which statement is most likely correct?

Physics
2 answers:
DENIUS [597]4 years ago
8 0

Answer:

the correct answer is B

Valentin [98]4 years ago
5 0

Answer:

It is D my beautiful children <3

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1. Current is usually the flow of
kolbaska11 [484]

Answer:

1. Current is usually the flow of <u>electrons</u>.

Explanation:

The flow of charges through a wire or conductor is called electric current.

7 0
3 years ago
Read 2 more answers
Some students fire a rocket of mass 0.150kg into the air. If at the top of it's flight it has a gravitational potential energy o
mamaluj [8]
PE=mgh
150J=(0.150)*(9.8)*h
h=102m
4 0
4 years ago
Consider the cross section to the right with an overall height h 4.2 inch, bottom flange plate width b1-2.5 inch, top flange pla
ICE Princess25 [194]

Answer: a) 1.98inch

b) 2.737 2.44

c) 0.497inch

d) 1.58inch

Explanation:

Solution is attached in the pictures below

7 0
3 years ago
Which of think following materials is the best is the best choice for an insulating material?
RSB [31]
You are correct, the answer is C. 

Good insulators are materials that do not allow heat, electricity, light or sound pass through easily. Materials like steel and silver (which are metals) are not good insulators because they make good conductors. They easily allow heat, electricity and the like pass through them. 

Thus, the answer is letter C. Rubber. 
7 0
3 years ago
The tub of a washer goes into its spin cycle, starting from rest and gaining angular speed steadily for 7.00 s, at which time it
Keith_Richards [23]

Answer:

The no. of revolutions does the tub turn while it is in motion is = 52.51 revolutions

Explanation:

Given data

\omega_1 = 0

\omega_2 = 5 \frac{rev}{sec}

Time taken = 7 sec

(1). The angular acceleration is given by

\alpha = \frac{d \omega}{dt}

\alpha  = \frac{5}{7}

\alpha  = 0.714 \frac{rev}{s^{2} }

We know that from the equation of motion

\omega_2^{2} =  \omega_1^{2} + 2 \alpha \theta_1

5^{2} = 0 + 2 (0.714) \theta_1

\theta_1 = 17.5 \ rev  -------- (1)

(2). The angular acceleration is given by

\alpha = \frac{d \omega}{dt}

\alpha = - \frac{5}{14}

\alpha = - 0.357 \frac{rev}{s^{2} }

We know that from the equation of motion

\omega_2^{2} =  \omega_1^{2} + 2 \alpha \theta_2

0^{2} = 5^{2} + 2 (-0.357) \theta_2

\theta_2 = 35.01 rev  -------  (2)

Total no of revolution made by the machine is

\theta = \theta_1 + \theta_2

\theta = 17.5 + 35.01

\theta = 52.51 rev

Therefore the no. of revolutions does the tub turn while it is in motion is = 52.51  rev

8 0
3 years ago
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