All categories

3 years ago

Why are Watson’s experiments considered controversial?

2 answers:

fomenos3 years ago

5 0

John Watson's experiments are considered controversial because D. They would be considered unethical today.

The Little Albert experiment exposed children, usually infants, first to things like rabbits, puppies, and hairballs. The children did not show fear of the items. However, once they were exposed to sudden loud sounds, rats, and stressful controlled situations. The goal of this experiment was to "condition phobia into a mentally stable child". However, these experiments are also failed in modern scientific testing. However, that doesn't make the Little Albert experiment as controversial as the unethical aspect does.

Hope I could help!

iris [78.8K]3 years ago

4 0

D, it is considered unethical today

You might be interested in

Question is attatched!

lina2011 [118]

All it does is lets him pull in a more convenient direction to raise the load. It has no effect on the required force.

4 0

3 years ago

Which of the following is a balanced chemical equation?

Natalija [7]

Explanation:e=mwS

and also yes it is i think

5 0

3 years ago

A quarterback is set up to throw the football to a receiver who is running with a constant velocity v⃗ rv→rv_r_vec directly away

Artist 52 [7]

Answer:

a) V_o,y = 0.5*g*t_c

b) V_o,x = D/t_c - v_r

c) V_o = sqrt ( (D/t_c - v_r)^2 + (0.5*g*t_c)^2)

d) Q = arctan ( g*t_c^2 / 2*(D - v_r*t_c) )

Explanation:

Given:

- The velocity of quarterback before the throw = v_r

- The initial distance of receiver = r

- The final distance of receiver = D

- The time taken to catch the throw = t_c

- x(0) = y(0) = 0

Find:

a) Find V_o,y, the vertical component of the velocity of the ball when the quarterback releases it. Express V_o,y in terms of t_c and g.

b) Find V_o,x, the initial horizontal component of velocity of the ball. Express your answer for V_o,x in terms of D, t_c, and v_r.

c) Find the speed V_o with which the quarterback must throw the ball.

Answer in terms of D, t_c, v_r, and g.

d) Assuming that the quarterback throws the ball with speed V_o, find the angle Q above the horizontal at which he should throw it.

Solution:

- The vertical component of velocity V_o,y can be calculated using second kinematics equation of motion:

y = y(0) + V_o,y*t_c - 0.5*g*t_c^2

0 = 0 + V_o,y*t_c - 0.5*g*t_c^2

V_o,y = 0.5*g*t_c

- The horizontal component of velocity V_o,x witch which velocity is thrown can be calculated using second kinematics equation of motion:

- We know that V_i, x = V_o,x + v_r. Hence,

x = x(0) + V_i,x*t_c

D = 0 + V_i,x*t_c

V_o,x + v_r = D/t_c

V_o,x = D/t_c - v_r

- The speed with which the ball was thrown can be evaluated by finding the resultant of V_o,x and V_o,y components of velocity as follows:

V_o = sqrt ( V_o,x^2 + V_o,y^2)

V_o = sqrt ( (D/t_c - v_r)^2 + (0.5*g*t_c)^2)

- The angle with which it should be thrown can be evaluated by trigonometric relation:

tan(Q) = ( V_o,y / V_o,x )

tan(Q) = ( (0.5*g*t_c)/ (D/t_c - v_r) )

Q = arctan ( g*t_c^2 / 2*(D - v_r*t_c) )

6 0

3 years ago

Snorkelers breathe through tubes that extend above the surface of the water. In prin- ciple, a snorkeler could go deeper with a

Yanka [14]

Answer:

h = 1.02 m

Explanation:

This is a fluid mechanics exercise, where the pressure is given by

P = $P_{atm}$ + ρ g h

The gauge pressure is

P - $P_{atm}$ = ρ g h

In this case the upper part of the tube we have the atmospheric pressure. and the diver can exert a pressure 10 KPa below the outside pressure, this must be the gauge pressure

$P_{m}$ = P - $P_{atm}$