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gulaghasi [49]
3 years ago
14

State three evidences that the particles of substances are in continuous motion

Chemistry
2 answers:
Over [174]3 years ago
4 0
Evidence. Three types of basic matter.
Matter is anything that occupies space and has mass. Thus, there are fundamentally three types of matter which is solid liquid and gas. But why do gases and liquids diffuse and not solids? It is because of the molecular structure of these components of matter. If we examine the molecular structure of gas the molecules are highly scattered and liquid has also almost the same structure as mediocrely scattered that these particles can easily slip through other substances unlike solid which is entirely intact.  <span>
</span>
Solnce55 [7]3 years ago
3 0

The three evidences that show that the particles of substances are in continuous motion are given below:

1. DIFFUSION: Diffusion is the movement of particles of a substance through a medium, from a region of higher concentration to a region of lower concentration. Particles of substances (solid, liquid or gas) tend to move from an area where more of them are present to an area where only few are present until they are evenly distributed. For example, a can of gasoline left in an open air can easily catch fire because the particles of gasoline can be easily carried by air to the nearest source of ignition.

2. OSMOSIS: Osmosis is the process by which solvent molecules move from a less concentrated solution to a more concentrated solution through a semi permeable membrane; the movement typically continues until the concentrations of solutes on both sides of the membrane are equal. Osmosis is a very crucial process in the biological systems of living organisms, where the plasma membrane, which is semi permeable in nature only allow specific small particles to pass through. Water molecules pass through the plasma membrane by diffusion via the phospholipid bilayers; osmosis thus provide the major mean via which water is moved in and out of living cells

3. BROWNIAN MOVEMENT: When a pollen grain, which is suspended in a drop of water is observed under a microscope, it will be seen that the pollen is moving about in a zig-zag manner. The zig zag movement of the pollen is due to the continuous movement of the particles of water on which the pollen was suspended. This phenomenon was first observed by a botanist, a British scientist called Robert Brown in 1827 and that was why the phenomenon was named after him.

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HELP PLEASE WITH 1 QUESTION.
Nata [24]
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8 0
4 years ago
If 14.5 kJ of heat were added to 485 g of liquid water, How much would its temperature increase?
olga55 [171]

<u>Answer:</u> The increase in temperature is 7.14°C

<u>Explanation:</u>

To calculate the change in temperature, we use the equation:

q=mc\Delta T

where,

q = heat absorbed = 14.5 kJ = 14500 J    (Conversion factor: 1 kJ = 1000 J)

m = mass of water = 485 g g

c = specific heat capacity of water = 4.184 J/g.°C

\Delta T = change in temperature = ?

Putting values in above equation, we get:

14500J=485g\times 4.184J/g.^oC\times \Delta T\\\\\Delta T=7.14^oC

Hence, the increase in temperature is 7.14°C

3 0
3 years ago
What is the percent composition of nitrogen in Ca(NO3)2?
MrMuchimi

Nitrogen in this compound has 2 atoms. 2 multiplied by its mass, 14.007, equals 28.014. Divide 28.014 by the molar mass of calcium nitrate: 28.014/164 = 0.17081. Multiply this by 100 to achieve its percentage: 0.17081 x 100 = 17.08%

8 0
4 years ago
What it the oxidation number for cl?<br> A. -2<br> B. +2<br> C. -1<br> D. +1
brilliants [131]

Answer:

c.

Explanation:

it is c.-1 because oxidation number of cl is-1

5 0
3 years ago
If the length, width, and height of a box are 10.00 cm, 7.25 cm and 3.00 cm, respectively, what is the volume of the box in unit
Blizzard [7]

<u>Answer:</u>

<u>For a:</u> The volume of the box is 217.5 mL

<u>For b:</u> The volume of the box is 0.2175 L

<u>Explanation:</u>

The box is a type of cuboid.

To calculate the volume of cuboid, we use the equation:

V=lbh

where,

V = volume of cuboid

l = length of cuboid = 10.00 cm

b = breadth of cuboid = 7.25 cm

h = height of cuboid = 3.00 cm

Putting values in above equation, we get:

V=10.00\times 7.25\times 3.00=217.5cm^3

  • <u>For a:</u>

To convert the volume of cuboid into milliliters, we use the conversion factor:

1mL=1cm^3

So,

\Rightarrow 217.5cm^3\times (\frac{1mL}{1cm^3})\\\\\Rightarrow 217.5mL

Hence, the volume of the box is 217.5 mL

  • <u>For b:</u>

To convert the volume of cuboid into liters, we use the conversion factor:

1L=1000cm^3

So,

\Rightarrow 217.5cm^3\times (\frac{1L}{1000cm^3})\\\\\Rightarrow 0.2175L

Hence, the volume of the box is 0.2175 L

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4 years ago
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