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givi [52]
3 years ago
7

Please help! Just answer these questions

Physics
1 answer:
Ivenika [448]3 years ago
5 0
1. is heliocentric because it means that the sun is in the center of the solar system
2. Winter solstice- the day of the year with the shortest hours of daylight- December 21 or 22
Summer solstice- the day of the year with the longest daylight- June 21 or 22
Spring equinox- the equinox in spring- march 21 or 22
Fall equinox- the time when the sun crosses the plane of the earth's equator- September 21 or 22
Hope this helps
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Could a person at the south pole see the north star, explain?? ​
9966 [12]

Answer:

If conditions are just right, you can see Polaris from just south of the equator.  Although Polaris is also known as the North Star, it doesn't lie precisely above Earth's North Pole. If it did, Polaris would have a declination of exactly 90 degree.

Explanation:

4 0
2 years ago
Read 2 more answers
What is the length of the x-component of the vector shown below?
ollegr [7]

Answer:

Option B. 8.1

Explanation:

From the question given above, the following data were obtained:

Angle θ = 71°

Hypothenus = 25

Adjacent = x

Thus, we can obtain the x component of the vector by using the cosine ratio as illustrated below:

Cos θ = Adjacent /Hypothenus

Cos 71 = x/25

Cross multiply

x = 25 × Cos 71

x = 25 × 0.3256

x = 8.1

Therefore, the x component of the vector is 8.1

4 0
3 years ago
A pelican hunts fish in the water. As the pelican flies above the water’s surface, why must it aim for the fish in a slightly di
GarryVolchara [31]

Answer

A

Explanation

The light the fish absorbs is sunlight, the light reflecting is UV

5 0
3 years ago
4. A 1200 kg car traveling North at 20.0 m/s collides with a 1400 kg car traveling South at 22.0 m/s. The two
Dvinal [7]

Answer:-2.61 m/s

Explanation:

This problem can be solved by the Conservation of Momentum principle, which establishes that the initial momentum p_{o} must be equal to the final momentum p_{f}:

p_{o}=p_{f} (1)

Where:

p_{o}=mV_{o}+MU_{o} (2)

p_{f}=(m+M)V_{f} (3)

m=1200 kg is the mass of the first car

V_{o}=20 m/s is the velocity of the first car, to the North

M=1400 kg is the mass of the second car

U_{o}=-22 m/s is the mass of the second car, to the South

V_{f} is the final velocity of both cars after the collision

mV_{o}+MU_{o}=(m+M)V_{f} (4)

Isolating V_{f}:

V_{f}=\frac{mV_{o}+MU_{o}}{m+M} (5)

V_{f}=\frac{(1200 kg)(20 m/s)+(1400 kg)(-22 m/s)}{1200 kg+1400 kg} (6)

Finally:

V_{f}=-2.61 m/s (7) This is the resulting velocity of the wreckage, to the south

7 0
3 years ago
a 2.00 kg object is moving east at 4.00 m/s when it collides with a 6 kg object that is initially at rest. after the collision t
baherus [9]

Answer:

v = 1.00 m/s east

Explanation:

Conservation of momentum

Let east be the positive direction

2.00(4.00) + 6.00(0.00) = 2.00(v) + 6.00(1.00)

v = 1.00 m/s east

The two items have stuck together.

6 0
2 years ago
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