Answer:
<em>The velocity of sound in the guitar string = 129.99 m/s</em>
Explanation:
Harmonics: A harmonic is a note with frequency equal to an integral multiple of that of the fundamental frequency.
<em>Note:</em> The harmonics of a string is the same as the harmonics of an open pipe.
f₆ = 3v/l ............................ Equation 1
making v the subject of the equation,
v = f₆l/3 ......................... Equation 2
Where f₆ = Is the sixth harmonics of the the string, v = velocity of sound in the guitar string, l = length of the guitar string.
<em>Given: </em>f₆ = 557.14 Hz, l = 70 cm = 0.7 m.
Substituting into equation 2
v = (557.14×0.7)/3
<em>v = 129.99 m/s</em>
<em>Thus the velocity of sound in the guitar string = 129.99 m/s</em>
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Answer:
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Answer:
option C
Explanation:
given,
mass of water = 4 Kg
Water is heated to = 800 W
time of immersion = 10 min
= 10 x 60 = 600 s
using equation of specific heat
Q = m S ΔT
S is the specific heat capacity of water which is equal to 4182 J/kg°C.
and another formula of heat
Q = Pt
now,
P t = m S ΔT
800 x 600 = 4 x 4182 x ΔT
ΔT = 29° C
temperature increased is equal to ΔT = 29° C
Hence, the correct answer is option C