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KonstantinChe [14]
3 years ago
11

A satellite dish is shaped like a paraboloid of revolution. This means that it can be formed by rotating a parabola around its a

xis of symmetry. The receiver is to be located at the focus. If the dish is 48 feet across at its opening and 4 feet deep at its center, where should the receiver be placed
Physics
1 answer:
pentagon [3]3 years ago
7 0

Answer:

Explanation:

Given dish width= 48ft

Depth = 4ft

Using equation of a parabola

x²= 4py

48² = 4p 4

4p = 576

P= 144ft

Thus the the receiver should be placed 144ft from t the vertex

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Answer:

Fan speed

Explanation:

because is the dependent variable

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The Answer that makes the most sense is C.
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5 0
3 years ago
A rifle fires a bullet at a target. The speed of the bullet is 600m/s. The target is located 400m away. How long does it take fo
Alex

0.67s

Explanation:

Given parameters:

Speed of bullet = 600m/s

Distance of target = 400m

Unknown:

Time taken for bullet to reach target = ?

Solution:

Speed is a physical quantity that expresses the rate of change of distance with time;

   Speed = \frac{distance}{time taken}

   Since time is unknown, we make it the subject of the expression;

   time = \frac{distance }{speed} = \frac{400}{600}

   time = 0.67s

Learn more:

Speed brainly.com/question/10048445

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5 0
3 years ago
Let's take two balls, each of radius 0.1 meters and charge them each to 3 microCoulombs. Then, let's put them on a flat surface
salantis [7]

Explanation:

First, we will calculate the electric potential energy of two charges at a distance R as follows.

                   R = 2r

                      = 2 \times 0.1 m

                      = 0.2 m

where,    R = separation between center's of both Q's. Hence, the potential energy will be calculated as follows.

                U = \frac{k \times Q \times Q}{R}

                    = \frac{8.98 \times 10^{9} \times (3 \times 10^{-6} C)^{2}}{0.1}

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As, both the charges are coming towards each other with the same energy so there will occur equal sharing of electric potential energy between these two charges.

Therefore, when these charges touch each other then they used to posses maximum kinetic energy, that is, \frac{U}{2}.

Hence,   K.E = \frac{U}{2}

                     = \frac{0.081}{2}

                     = 0.0405 J

Now, we will calculate the speed of balls as follows.

                 V = \sqrt{\sqrt{\frac{2 \times K.E}{m}}

                     = \sqrt{\sqrt{\frac{2 \times 0.0405}{4 kg}}

                     = 0.142 m/s

Therefore, we can conclude that final speed of one of the balls is 0.142 m/s.

6 0
3 years ago
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