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vovikov84 [41]
3 years ago
5

HELPpPpo ASAP

Physics
1 answer:
Stella [2.4K]3 years ago
7 0

Answer:

Explanation:

The only one NOT true is D. The label for acceleration is meters/sec/sec or

\frac{m}{s^2}

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777dan777 [17]
<span>One leg is  = 12 m, and the other leg is 16 m. </span>
3 0
2 years ago
A 1000.0 kg truck accelerates from 20.0 m/s to 25.0 m/s over a distance of 300.0 m. What is the average net force on the truck?
choli [55]

Answer:

The average net force on the truck is 375 Newtons.

Explanation:

Using Newton's 3rd equation of motion, we have :

v^{2} - u^{2} = 2×a×s

where, v = final velocity = 25 m/s

u = initial velocity = 20 m/s

a = acceleration

s = distance traveled = 300 m

Using these values in the above equation, we get acceleration = 0.375 m/s^{2}

Using Newton's second law, we have:

F=m×a

where m = mass = 1000 kg

a= acceleration = 0.375 m/s^{2}

Putting values we have F=375 N

3 0
3 years ago
2<br><br> How does Descartes' "quality of motion" differ from the modern<br><br> momentum?
Rzqust [24]

Answer: Descartes was more of speed which defers from modern day velocity.

Explanation:

Descartes law if conservation referred or defined “motion” rather than “momentum” as what is obtainable in today's world as ”speed” the rate at which something moves rather than “velocity” which is a product of speed and direction. So in conclusion Descartes was more of speed which defers from modern day velocity.

6 0
2 years ago
The Atoms Family
ioda
What question are you asking?
4 0
2 years ago
Un móvil se encuentra en la posición inicial x0 = 22 m, y se mueve con velocidad 5 m/s. Calcula la posición en la que se encuent
Brilliant_brown [7]

Answer:

La posición en la que se encuentra el móvil en el instante t = 30 s es 172 m.

Explanation:

El movimiento rectilíneo uniforme (MRU) es el movimiento que describe un cuerpo o partícula a través de una línea recta a velocidad constante.

La distancia recorrida,  x , por un móvil que tiene un MRU con un velocidad  v  durante el intervalo de tiempo  t  es:

x= x0 + v*t

donde x0 es la posición inicial.

En este caso:

  • x0= 22 m
  • v= 5 m/s
  • t= 30 s

Reemplazando:

x= 22 m + 5 m/s* 30 s

Resolviendo:

x= 22 m + 150 m

x= 172 m

<u><em>La posición en la que se encuentra el móvil en el instante t = 30 s es 172 m.</em></u>

8 0
2 years ago
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