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vovikov84 [41]
3 years ago
5

HELPpPpo ASAP

Physics
1 answer:
Stella [2.4K]3 years ago
7 0

Answer:

Explanation:

The only one NOT true is D. The label for acceleration is meters/sec/sec or

\frac{m}{s^2}

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Which statement best describes what is happening at
12345 [234]

Answer:

Water is absorbing heat.

Explanation:

Water is able to absorb heat

-<u> without increasing much in temperature</u> - better than many substances.

This is because for water to increase in temperature, water molecules must be made to move faster within the water; this requires breaking hydrogen bonds, and the breaking of hydrogen bonds absorbs heat.

5 0
3 years ago
How are sound waves similar to light waves?
Tom [10]

Answer:

Sound and light are similar in that both are forms of energy that travel in waves.

Explanation:

They both have properties of wavelength, freqency and amplitude. ... Sound can only travel through a medium (substance) while light can travel through empty space. Sound is a form of mechanical energy caused by vibrations of matter.

6 0
3 years ago
Read 2 more answers
A ray of light is moving from a material having a high indexof refraction into a material with a lower index of refraction.
luda_lava [24]

(a) Away from the normal

We can find the direction of bending of the ray of light by using Snell's equation:

n_1 sin \theta_1 = n_2 sin \theta_2

where we have:

n1, n2: index of refraction of the first and second medium

\theta_1, \theta_2; angle that the incident and the refracted ray form with the normal to the surface

Here, the light ray moves from a material with high index of refraction to a material with lower index, so we have

n_1 > n_2

Re-arranging Snell's law we find

sin \theta_2 = \frac{n_1}{n_2} sin \theta_1

since we have

\frac{n_1}{n_2}>1

this implies

sin \theta_2 > sin \theta_1\\\theta_2 > \theta_1

so the ray of light bends away from the normal.

(b) The wavelength is greater in the second material (the one with lower index of refraction)

The wavelength of the light in a medium is given by

\lambda=\frac{\lambda_0}{n}

where

\lambda_0 is the wavelength of the light in a vacuum

n is the refractive index

The equation can be rewritten as

\lambda_0 = \lambda_1 n_1 = \lambda_2 n_2

and again it can be rewritten as

\lambda_2 = \frac{n_1}{n_2} \lambda_1

where

\lambda_1 = 600 nm\\\frac{n_1}{n_2}>1

Therefore, we have that the wavelength in the second medium (the one with lower index of refraction) is longer than the wavelength in the first medium.

(c) The frequency remains the same

Wavelength and speed of a light ray depend on the medium in which the wave is travelling through, however the frequency does not depend on that, so it remains the same in the two mediums.

8 0
3 years ago
during a crash, the acceleration was less than 30g. Calculate the force on a 70 kg person accelerating at this rate.
Igoryamba

Answer:

less than 20580 N

Explanation:

According to the newton's second law of motion

Force = mass * acceleration

(assuming gravitational acceleration =9.8 m/s2 )

acceleration = 30*9.8 = 294 m/s2

acting Force = 70 * 294

                     = 20580 N

Since the acceleration was less than 30g  , acting force should also be less than 20580 N

4 0
3 years ago
The image produced by an object is –10.0 cm from a concave mirror that has a focal length of 5.0 cm. The distance of the object
Gennadij [26K]
Given:
Focal length: 5.0 cm
image produced: -10.0 cm

mirror equation:   1/di + 1/do = 1/f

Look for the actual distance of the object from the mirror. Solve for do.

1/do + 1/(-10) = 1/5
1/do = 1/5 + 1/10
1/do = (1/5 * 2/2) + (1/10 * 1/1)
1/do = 2/10 + 1/10
1/do = 3/10
10 = 3do
10/3 = do
3.33 = do

The distance of the object from the mirror, rounded to the nearest centimeter is 3 cm.
3 0
4 years ago
Read 2 more answers
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