Question

A plane is flying horizontally with speed 292 m/s at a height 3880 m above the ground, when a package is dropped from the plane. the acceleration of gravity is 9.8 m/s 2 . neglecting air resistance, when the package hits the ground, the plane will be 1. ahead of the package. 2. directly above the package. 3. behind the package. 008 (part 2 of 4) 10.0 points what is the horizontal distance from the release point to the impact point?

Answer 1

The plane is straight above the package when it hits the ground. 
Find in what way long a free fall from a height of 4240 m takes: s = 1/2 gt^2 
t^2 = 2s/g 
t^2 = 2* 3880/9.8 = 791.8367
t = √791.8367
t = 28.1396 seconds 
Now find the horizontal displacement with v = 292 m/s in 28.1396 s: 
s = v*t 
s = 292 * 28.1396 = 8216.76 m