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Elden [556K]
3 years ago
12

Two electrons travel towards each other at 0.2 c parallel to the laboratory x-axis. What is the relative velocity of one electro

n with respect to the other? What is the relative velocity of the two electrons with respect to the lab?
Physics
1 answer:
Leya [2.2K]3 years ago
5 0

1) In the reference frame of one electron: 0.38c

To find the relative velocity of one electron with respect to the other, we must use the following formula:

u'=\frac{u-v}{1-\frac{uv}{c^2}}

where

u is the velocity of one electron

v is the velocity of the second electron

c is the speed of light

In this problem:

u = 0.2c

v = -0.2c (since the second electron is moving towards the first one, so in the opposite direction)

Substituting, we find:

u'=\frac{0.2c+0.2c}{1+\frac{(0.2c)(0.2c)}{c^2}}=\frac{0.4c}{1+0.04}=0.38c

2) In the reference frame of the laboratory: -0.2c and +0.2c

In this case, there is no calculation to be done. In fact, we are already given the speed of the two electrons; we are also told that they travel in opposite direction, so their velocities are

+0.2c

-0.2c

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Just for a place to work with, I picked the Yakima Valley Junior College, at the
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Here's how I would do it:

-- The altitude of the due-south point on the celestial equator is always
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-- The highest above the celestial equator that the ecliptic ever gets
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-- The mean inclination of the moon's orbit to the ecliptic is 5.14°, so
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This sets the limit of the highest in the sky that the moon can ever appear.

90° - 46.585° + 23.5° + 5.14° = 72.1° above the horizon .

That doesn't happen regularly.  It would depend on everything coming
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Depending on the time of year, that can be any time of the day or night.

The most striking combination is at midnight, within a day or two of the
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