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2 years ago

Calculate the volume at STP of the following compounds: 0,01 mol of hydrogen chloride gas.

Physics

1 answer:

Nady [450]2 years ago

8 0

The volume at STP of the following compounds: 0,01 mol of hydrogen chloride gas is 0.224 L.

As we know, one mole of a gaseous substance occupies 22.4 litre, so volume occupied by 0.01 mole hydrogen chloride gas is 0.224 L.

The equation characterising the states of hypothetical gases stated mathematically by combinations of empirical and physical constants is known as the Ideal Gas Equation. It is the relationship between pressure, volume, moles, and temperature.

The ideal gas equation was developed by merging many gas laws, including Charles' law, Boyle's law, Gay-law, Lussac's and Avogadro's law. The equation of state of a hypothetical ideal gas is the ideal gas law. It approximates the behaviour of gases under certain conditions.

An ideal gas is a fictitious gas composed of randomly moving particles that collide in totally elastic collisions. Even while there is no such thing as an ideal gas, most gases tend to exhibit these characteristics as their density lowers. This occurs because the intermolecular distances between gas molecules are so great that they do not interact.

Hence, in all the standard conditions of temperature, pressure and number of moles, the molar volume is 22.4 Litre which is also considered as a standard.

Learn more about ideal gas equation brainly.com/question/4147359

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What material or device prevents the conducting of electricity?

PtichkaEL [24]

Answer:

Explanation:

An insulator. You can see ceramic insulators on telephone poles and power poles if you look carefully. If you live in a city, somewhere in that city is a power station. The insulators are huge. They have to be. The currents are very large in many cases.

4 0

4 years ago

To calibrate the calorimeter electrically, a constant voltage of 3.6 V is applied and a current of 2.6 A flows for a period of 3

hodyreva [135]

Answer : The correct option is, (c) $3.7\times 10^2J/^oC$

Explanation :

First we have to calculate the energy or heat.

Formula used :

$E=V\times I\times t$

where,

E = energy (in joules)

V = voltage (in volt)

I = current (in ampere)

t = time (in seconds)

Now put all the given values in the above formula, we get:

$E=(3.6V)\times (2.6A)\times (350s)$

$E=3276J$

Now we have to calculate the heat capacity of the calorimeter.

Formula used :

$C=\frac{E}{\Delta T}=\frac{E}{T_{final}-T_{initial}}$

where,

C = heat capacity of the calorimeter

$T_{initial}$ = initial temperature = $20.3^oC$

$T_{final}$ = final temperature = $29.1^oC$

Now put all the given values in this formula, we get:

$C=\frac{3276J}{(29.1-20.3)^oC}$

$C=372.27J/^oC=3.7\times 10^2J/^oC$

Therefore, the heat capacity of the calorimeter is, $3.7\times 10^2J/^oC$

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3 years ago

The inductor in a radio receiver carries a current of amplitude 200 mA when a voltage of amplitude 2.4 V is across it at a frequ

zzz [600]

Answer:

The value of the inductance is 1.364 mH.

Explanation:

Given;

amplitude current, I₀ = 200 mA = 0.2 A

amplitude voltage, V₀ = 2.4 V

frequency of the wave, f = 1400 Hz

The inductive reactance is calculated;

$X_l = \frac{V_o}{I_o} \\\\X_l = \frac{2.4}{0.2} \\\\X_l =12 \ ohms$

The inductive reactance is calculated as;

$X_l = \omega L\\\\X_l = 2\pi fL\\\\L = \frac{X_l}{2 \pi f}$

where;

L is the inductance

$L = \frac{12}{2 \pi \times \ 1400} \\\\L = 1.364 \times \ 10^{-3} \ H\\\\L = 1.364 \ mH$

Therefore, the value of the inductance is 1.364 mH.

7 0

3 years ago

Calculate the height of a cliff if it takes 2.35 s for a rock to hit the ground when it is thrown straight up from the cliff wit

pantera1 [17]

Answer:

height of a cliff is 45.86 m

Explanation:

u=8 m/s

t=2.35 s

the height of the cliff is

$S=ut+\frac{1}{2} at^2\\S=8\times2.35+\frac{1}{2} \times 9.8 \times 2.35^2\\S=45.86 m$

7 0

3 years ago

One mole of a gas is placed in a closed system with a 20 L vessel initially at T = 300 K. The vessel is then isothermally expand

Elden [556K]

Answer:

Given that

P = RT/V + a/V²

We know that

H= U + PV

For T= Constant (ΔU=0)

ΔH= ΔU +Δ( PV)

ΔH= Δ( PV)

P = RT/V + a/V²

P V= RT + a/V

dH/dV = d(RT + a/V)/dV

dH/dV = - a/V²

So the expression of dH/dV

$\dfrac{dH}{dV}=\dfrac{-a}{V^2}$

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$\Delta H=nRT\ln{\dfrac{V_2}{V_1}}$ (ΔU=0)

Now by putting the all values

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$\Delta H=1\times 0.08206\times 300\ln{\dfrac{40}{20}}$

ΔH = 17.06 L.atm

8 0

3 years ago