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2 years ago

A 550N object has a coefficient of .012 against a smooth surface. What

Physics

1 answer:

Brrunno [24]2 years ago

4 0

Vertically, the object is in equilibrium, so that the net force in this direction is

∑ F (vertical) = n - mg = 0

where n is the magnitude of the normal force due to the contact between the object and surface. You're given that the object's weight is mg = 550 N, so n = 550 N as well.

Horizontally, the net force would be

∑ F (horizontal) = p - f = 0

where p is the magnitude of the applied force and f is the magnitude of (kinetic) friction opposing p. Now,

f = 0.012n = 0.012 (550 N) = 6.6 N

so that you need to apply a force of p = 6.6 N to keep the object sliding at a steady pace.

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3 years ago

Which two statements are true about the wave shown?

Andreyy89

Answer:

B and C

Explanation:

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2 years ago

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2 years ago

Two sound waves have equal displacement amplitudes, but wave 1 has two-thirds the frequency of wave 2. What is the ratio of the

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$\dfrac{I_1}{I_2}=\dfrac{4}{9}$

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2 years ago

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