What is your theory on frame of reference?
Answer:
It is the idea of seeing something from a different perspective
Explanation:
Hope this helps!
 
        
             
        
        
        
Answer:
Explanation:
Given that,
Mass of the heavier car m_1 = 1750 kg
Mass of the lighter car m_2 = 1350 kg
The speed of the lighter car just after collision can be represented as follows


b) the change in the combined kinetic energy of the two-car system during this collision

substitute the value in the equation above

Hence, the change in combine kinetic energy is -2534.78J
 
        
             
        
        
        
Answer:
  
Explanation:
For this exercise we must use the principle of conservation of energy
starting point. The proton very far from the nucleus
           Em₀ = K = ½ m v²
final point. The point where the proton is stopped (v = 0)
           Em_f = U = q V
where the potential is
           V = k Ze / r²
Let us consider that all the charge of the nucleus is in the center, therefore r is the distance from this point to the proton that is approaching
Energy is conserved
           Em₀ = Em_f
            ½ m v² = e ( )
)
            
with this expression we can find the closest approach distance (r)