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NeTakaya
3 years ago
12

Why is mercury the only metal to have been used in thermometers

Chemistry
1 answer:
MArishka [77]3 years ago
6 0
I think because its the only one to be liquid  at  normal temperatures.
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Burning coal releases the following pollutants except
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B stratospheric zone
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Which of the following correctly describes a compound?
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I think its c, it makes sense to me to be c
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Can someone explain the steps for balancing chemical equations in depth?
m_a_m_a [10]

Answer:

Steps explained below

Explanation:

To explain balancing of chemical equations, I will make use of an example equation where Hydrogen and oxygen react to form water.

H2 + O2 = H2O

Now, the equation I've listed above is an unbalanced chemical equation. It can be balanced by the following steps;

Step 1: Identify the elements on both the left Hand side and the right hand side.

In this case;

on the left hand side, we have H and O.

On the right hand side, we have H and I also.

Step 2: Identify the number of atoms of each element on both the left and right hand sides.

On the left, H has 2 atoms and O has 2 atoms.

On the right, H has 2 atoms and O has 1 atom.

Step 3: For the equation to be balanced, the number of atoms of each element on the right and left hand side must be the same.

Thus,

O on the left hand side has 2 atoms but on the right hand side it has 1 atom. Thus, we will multiply O on the right by 2 to balance what we have on the left.

So, we now have;

H2 + O2 = 2H2O

Step 4: Check equation: We now have;

H2 + O2 = 2H2O

Our left hand side remains 2 atoms of H and 2 atoms of O. But on the right, we now have;

2 atoms O and 4 atoms of H.

Which means atoms of H is not balanced with the left side.

Step 5: rebalance equation: To rebalance, we multiply H on the left by 2 to give us 2 × 2 = 4 atoms.

Thus, we now have;

2H2 + O2 = 2H2O

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Sm is the answer

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3 years ago
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Mass of water 50.003 g 24 95C Temperature of water Specific heat capacity for water 4.184J/g C Mass of metal 3.546 Temperature o
Norma-Jean [14]

Correct Question :

Mass of water = 50.003g

Temperature of water= 24.95C

Specific heat capacity for water = 4.184J/g C

Mass of metal = 63.546 g

Temperature of metal 99.95°C

Specific heat capacity for metal ?

Final temperature = 32.80°C

In an experiment to determine the specific heat of a metal student transferred a sample of the metal that was heated in boiling water into room temperature water in an insulated cup. The student recorded the temperature of the water after thermal equilibrium was reached. The data we shown in the table above. Based on the data, what is the calculated heat absorbed by the water reported with the appropriate number of significant figures?

Answer:

1642 J

Explanation:

Given:

Mass of water = 50.003g

Temperature of water= 24.95C

Specific heat capacity for water = 4.184J/g C

Mass of metal = 63.546 g

Temperature of metal 99.95°C

Specific heat capacity for metal ?

Final temperature = 32.80° C

To calculate the heat absorbed by water, Q, let's use the formula :

Q = ∆T * mass of water * specific heat

Where ∆T = 32.80°C - 24.95°C = 7.85°C

Therefore,

Q= 7.85 * 50.003 * 4.184

Q = 1642.32 J

≈ 1642 J

8 0
3 years ago
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