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3 years ago

Look at the diagram. Which shows the correct arrangement of electrons in water?

Chemistry

2 answers:

mariarad [96]3 years ago

6 0

Answer:

Option 4

Explanation:

In water molecule, oxygen has -2 charge on it while the hydrogen has +1 charge and one atom of oxygen combines with two hydrogen atoms. A hydrogen need only two electrons to complete its octet (one electron is its own the second electron is shared by oxygen) and a oxygen needs 8 electrons (It has six of its own and two are shared by two hydrogen atom).

Hence, option 4 is correct

Ad libitum [116K]3 years ago

4 0

Answer:

Option 2

It's more balanced than the others

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A scientist finds that one volume of an unknown gas X combines with two volumes of another gas Y to form two volumes of a new ga

MariettaO [177]

Answer:

Gas X

Explanation:

The given reaction can be written in the form of chemical equation as shown below as:

$X+2Y\rightarrow 2XY_2$

According to law of conservation of mass, the moles of each substance in the reaction must be equal on both reactant and product side.

Also, the question asks for the gas which is diatomic. $XY_2$ cannot be diatomic as the formula contains 3 atoms.

Between gas X and gas Y , <u>X has to be diatomic for the reaction to balance </u>as:

$X_2+2Y\rightarrow 2XY_2$

3 0

3 years ago

The density of an aqueous solution of nitric acid is 1.64 g/mL and the concentration is 1.85 M. What is the concentration of thi

galina1969 [7]

Answer:

Mass % of the solution = 7.1067 %

Explanation:

Given :

Molarity of nitric acid solution = 1.85 M

Density of the solution = 1.64 g/mL

<u>Molarity of a solution is defined as the number of moles of solute present in 1 liter of the solution.</u>

$Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}$

Lets, consider the volume of the solution = 1 L

Thus,

Moles of nitric acid present in the solution:

$Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}$

$Moles of Nitric acid=Molarity \times {Volume\ of\ the\ solution}$

So,

Moles of Nitric acid = 1.85 moles

Molar mass of nitric acid = 63 g/mol

The mass of Nitric acid can be find out by using mole formula as:

$moles=\frac{Mass\ taken}{Molar\ mass}$

Thus,

$Mass\ of\ Nitric\ acid=Moles \times Molar mass}$

$Mass\ of\ Nitric\ acid=1.85 g \times 63 g/mol}$

<u>Mass of Nitric acid = 116.55 g</u>

Also,

$Density=\frac{Mass}{Volume}$

Given : Density = 1.64 g/mL

Also, 1 L = 10³ mL

Volume of the solution is 1000 mL

So, mass of the solution:

$Mass\ of\ the\ solution=Density \times {Volume\ of\ the\ solution}$

$Mass\ of\ the\ solution=1.64 g/mL \times {1000 mL}$

<u>Mass of the solution = 1640 g</u>

Mass % is defined as the mass of solute in 100 g of the solution. The formula for the calculation of mass % is shown below:

$Mass \% =\frac{Mass\ of\ the\ solute}{Mass\ of\ the\ solution} \times {100}$

So,

$Mass \%=\frac{116.55}{1640} \times {100}$

6 0

3 years ago

Which applies to fision

lara [203]

Wasssssssupppp with you

6 0

3 years ago

Read 2 more answers

How to calculate formal charge on a lewis structure

o-na [289]

Answer:

count how many electrons it 'owns'

3 0

2 years ago

What are the half-reactions for a galvanic cell with Zn and Mg electrodes?

Alona [7]

the half-reactions

cathode : Zn²⁺ (aq) + 2e⁻ ---> Zn (s)

anode : Mg (s) → Mg²⁺ (aq) + 2e−

a balanced cell reaction

Zn²⁺(aq) + Mg(s)→ Zn(s) + Mg²⁺ (aq)

<h3 /><h3>Further explanation</h3>

Given

Zn and Mg electrodes

Required

The half-reactions for a galvanic cell

Solution

To determine the reaction of a voltaic cell, we must determine the metal that serves as the anode and the metal that serves as the cathode.

To determine this, we can either know from the standard potential value of the cell or use the voltaic series

1. voltaic series

The more to the left, the metal is more reactive (easily release electrons) and the stronger reducing agent

So the metal on the left will easily undergo oxidation and function as anode

Since Mg is located to the left of Zn, then Mg functions as anode and Zn as a cathode

2. Standard potentials cell of Mg and Zn metals :

Mg2+ + 2e– → Mg E° = -2,35 V

Zn2+ + 2e– → Zn E° = -0,78 V

The anode has a smaller E°, then Mg is the anode and Zn is the cathode.

7 0

3 years ago