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Firlakuza [10]
3 years ago
8

If the input force applied to one end of a first-class lever is 8 N, and the fulcrum is located 6 m away from the input force bu

t 3 m away from the output force, what will be the resulting output force?
Chemistry
1 answer:
MatroZZZ [7]3 years ago
4 0

Answer:

16 N

Explanation:

The ratio of output force to the input force is called mechanical advantage of the lever. Also, the ratio of input arm distance to the output arm distance is called mechanical advantage of the lever.

We have,

Input force = 8 N

Input arm distance = 6 m

Output arm distance = 3 m

We need to find the resulting output force. So,

\dfrac{F_o}{8}=\dfrac{6}{3}\\\\F_o=16\ N

So, the resulting output force is 16 N.

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A pencil has a density of .655 g/ml. It has a mass of 3.5g. What is its volume
Leviafan [203]

Answer:

<h3>The answer is 5.34 mL</h3>

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

volume =  \frac{mass}{density}\\

From the question

mass = 3.5 g

density = 0.655 g/mL

We have

volume =  \frac{3.5}{0.655}  \\  = 5.343511450...

We have the final answer as

<h3>5.34 mL</h3>

Hope this helps you

5 0
3 years ago
How are energy and mass connected during the formation of an atom?
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Energy is released and mass is reduced
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Describe in detail, the Maillard Reaction.
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In the process, hundreds of different flavor compounds are created. These compounds in turn break down to form yet more new flavor compounds, and so on. Each type of food has a very distinctive set of flavor compounds that are formed during the Maillard reaction. It is these same compounds that flavor scientists have used over the years to create artificial flavors.
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1.5L of water is boiled to steam at a temperature of 100 degrees Celsius and creates 3.5atm of pressure on the container. How ma
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5 0
3 years ago
When 16 g of methane (CH4) and 32 g of oxygen (O2) reacted to produce carbon dioxide and water, 11 g of carbon dioxide was produ
Aliun [14]

Answer:

Percent yield = 50%

Explanation:

Given data:

Mass of CH₄ = 16 g

Mass of O₂ = 32 g

Mass of CO₂ = 11 g

Percent yield of CO₂ = ?

Solution:

Chemical equation:

CH₄ + 2O₂    →  CO₂ + 2H₂O

Number of moles of CH₄:

Number of moles = mass/ molar mass

Number of moles = 16 g /16 g/mol

Number of moles = 1 mol

Number of moles of O₂:

Number of moles = mass/ molar mass

Number of moles = 32 g /32 g/mol

Number of moles = 1 mol

Now we will compare the moles of CO₂ with both reactant.

                             O₂             :            CO₂

                              2              :               1

                              1               :          1/2×1= 0.5 mol

                          CH₄              :            CO₂

                             1               :               1

Number of moles of CO₂ produced by oxygen are less so it will limiting reactant.

Theoretical yield:

Mass of CO₂:

Mass = number of moles × molar mass

Mass = 0.5 mol × 44 g/mol

Mass = 22 g

Percent yield:

Percent yield = actual yield / theoretical yield × 100

Percent yield = 11 g/ 22 g × 100

Percent yield = 50%

3 0
3 years ago
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