Answer
option (B) is right answer
Sry I'm a minor and do not have the amount of brain cells to compute this equation. :')
A because it’s basically a diagram to help you understand it
answer is o²
please agree my answer and provide me more question
Answer:- -2260 kj.
Solution:- It could easily be solved using dimensional analysis. From given information, the enthalpy change for the combustion of 2.00 grams of propane is -102.5 kj. It asks to calculate the enthalpy change in same conditions for the combustion of 1 mole of propane.
We convert 1 mole of propane to grams using molar mass(44.1 gram per mol) and then calculate the heat using the given information as:
= -2260 kj
Hence, the enthalpy change for the combustion of 1 mol of propane is -2260 kj.