a)
The volume of the sports hall can be calculated using the equation
where
a, b, c are the measures of the sizes of the hall
For the sport hall in this problem, we have
a = 80 m
b = 40 m
c = 15 m
Substituting into the equation, we find
b)
Being a gas, the air fills the whole sport halls, therefore its volume is equal to the volume of the sports hall.
The relationship between the mass, the volume and the density of the air is
where
is the density
m is the mass
V is the volume
Here we have:
Solving for m, we find the mass of air:
Answer:
10 to 15 seconds
Explanation:
because I don't know but rarity is a strong force and it don't take long for a ball to come down
Answer:
9.9 m/s
Explanation:
Given:
Δy = 5 m
v = 0 m/s
a = -9.8 m/s²
Find: v₀
v² = v₀² + 2aΔy
(0 m/s)² = v₀² + 2 (-9.8 m/s²) (5 m)
v₀ = 9.9 m/s
Answer:
The girl will move with constant velocity
Explanation:
If after a certain time t_0 the velocity of the girl is v_0 =gt_0 and the upward force on the girl due to rope is mg ,where g is gravitational acceleration. Then the girl will move down with the constant velocity v_0 .
The girl will move with constant velocity,as explained above.
The maximum speed of the car is 24.3 m/s
Explanation:
For a car moving along an unbanked turn, the frictional force provides the centripetal force required to keep the car in circular motion. Therefore, we can write:
where the term on the left is the frictional force while the term on the right is the centripetal force, and where
is the coefficient of friction between the tires and the road
m is the mass of the car
is the acceleration of gravity
v is the speed of the car
r = 150 m is the radius of the curve
Solving for v, we find the (maximum) speed at which the car can move along the turn:
For speed larger than this value, the frictional force is no longer enough to keep the car along the turn.
Learn more about circular motion:
brainly.com/question/2562955
brainly.com/question/6372960
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