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MissTica
3 years ago
9

PLEASE HELP! I will give brainliest and ten points!

Physics
2 answers:
Dmitry_Shevchenko [17]3 years ago
4 0

I need help with this too! I also do Connexus

Andrews [41]3 years ago
3 0

1)

Answer:

t = 3.64 s

Explanation:

As we know that the speed of the rock in vertical direction is ZERO

so here we will have

\Delta Y = \frac{1}{2}gt^2

64.8 = \frac{1}{2}(9.8)t^2

64.8 = 4.9 t^2

t = 3.64 s

2)

Answer:

The package appears to fall straight downwards

Explanation:

Since the package is dropped from the plane so the horizontal speed of the plane and package will be same

So here the package will always appear vertically down the plane

So here it will appear to move vertically down

3)

Answer:

8 cm to the right and 16 cm below

Explanation:

After one tringlet the position of the object is

x = 4 cm

y = 4 cm

Now we know that

x = v_x t

y = \frac{1}{2}gt^2

so here x coordinate is proportional to the time while y coordinate is square proportional to the time

so here in x direction it will move double distance in double time while in y direction its distance becomes 4 times

so we have

x = 8 cm

y = 16 cm

4)

Answer:

y = 0.945 m

Explanation:

distance of the home plate

d = 60 ft 6 in

d = 60.5\times 0.3048m

d = 18.44 m

now the time taken by ball to reach the home plate

t = \frac{d}{v}

t =\frac{18.44}{42} = 0.44 s

Now the distance dropped by the ball in same time

y = \frac{1}{2}gt^2

y = \frac{1}{2}(9.8)(0.44^2)

y = 0.945 m

5.

Answer:

d = 282 m

Explanation:

Time taken by the packet to reach the waves is given as

y = \frac{1}{2}gt^2

55 = \frac{1}{2}(6.91)t^2

t = 3.99 s

now in the same time distance moved by the packet

d = vt

d = 70.6 \times 3.99

d = 282 m

7.

Answer:

Between B to C

Explanation:

While moving downwards under gravity the attraction force of Earth will increase the speed

So its speed will increase during its return journey from B to C

8.

Answer:

y = 2040 m

Explanation:

given that

v_x = 50 m/s

\Delta x = 1000 m

now the time taken by the ball to reach the given distance is

t = \frac{d}{v}

t = \frac{1000}{50} = 20 s

now in the same time the vertical distance moved by it

y = v_y t - \frac{1}{2}gt^2

y = 200(20) - \frac{1}{2}(9.8)(20^2)

y = 2040 m

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Answer:

The volume of the highway's asphalt will be 6,400 cubic meters.

Explanation:

Volume is the overall magnitude of the three dimensions of a given object, that is, its width, length and depth. Thus, to obtain the volume of a certain object, its width must be multiplied by its length and this result in turn by its depth: W x L x D.

Thus, in this case, the highway has a width of 8 meters, a height of 4 cm and a depth of 20 km. As a first measure, all units of measurement must be expressed in a uniform way, for which the meter will be used in this case. Thus, the width of the highway will not vary, while its height will go from 4 cm to 0.04 meters (4/100), and its length will go from 20 km to 20,000 meters (20 x 1,000).

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8 x 0.04 x 20,000 = Volume

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8 0
3 years ago
a bullet fired straight through a board 0.10 mm thick strikes the board with a speed of 480 m/sm/s, has constant acceleration th
vekshin1

the average acceleration of the bullet through the board   -55657×10⁵ m/s²

acceleration-  Rate of change of velocity with respect to time.

S = 0.10 mm = 10⁻⁵ m  ( distance)          [∵ 1mm = 10⁻³]

u =  480 m/s (initial velocity)

v = 345 m/s (final velocity)

As we know the 3rd equation of motion.  

v² = u² + 2aS

a = ? ( acceleration)

using these values in equation we get

(345)² = (480)² + 2×a× 10⁻⁵

a = (345)² -  (480)² / 2× 10⁻⁵

a =  -55657×10⁵ m/s²

The negative sign shows that the direction of acceleration is opposite of velocity thus bullet is slowing down.

the average acceleration of the bullet through the board  -55657×10⁵ m/s²

The given question is incomplete. The complete question is.

a bullet fired straight through a board 0.10 mm thick strikes the board with a speed of 480 m/sm/s, has constant acceleration through the board, and emerges with a speed of 345 m/sm/s.

What is the average acceleration of the bullet through the board/?

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1 year ago
A point source at the origin emits sound of frequency 175 Hz uniformly in all directions. On the x-axis at x=100 m, the sound in
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Answer:

Multiple answers:

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2.Intensity 160m I=17.6W/m^{2}

3. dB = 77.3

4. f=178.5 Hz

Explanation:

First one comes from the expression

I=\frac{P}{4\pi r^{2} }

where<em> I </em>is the intensity, <em>P </em>is the power and <em>r </em>is the radio of the spherical wave, or in this case, the distance <em>x</em>. I solved for the Power by multiplying Intensity with the area (4\pi x^{2}

Second one is done with:

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Solving for Intensity 2, the result mentioned.

The third is simply computed with

dB=10*log\frac{I}{10^{-12} }

And finally the last one is done with doppler effect, taking into account the speed of the air as in 10ºC 337m/s.

f=f_{initial} *(\frac{s+v_{receiver} }{s+v_{source} } )

Where <em>Finitial</em> is the frequency emitted and <em>s</em> is the speed of the sound. The wind blowing in positive is, in principle, going away of the observer.

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No two electrons in an atom or molecule may have the same four electronic quantum numbers, according to the Pauli Exclusion Principle. Only two electrons can fit into an orbital at a time, hence they must have opposing spins.

<h3>What is Pauli's exclusion principle ?</h3>

According to Pauli's Exclusion Principle, no two electrons in the same atom can have values for all four of their quantum numbers that are exactly the same. In other words, two electrons in the same orbital must have opposing spins and no more than two electrons can occupy the same orbital.

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