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NeX [460]
1 year ago
15

calculate the tension in the horizontal rope. (the horizontal and the vertical ropes are not connected to each other. they are b

oth independently attached to the end of the boom.)
Physics
1 answer:
Brilliant_brown [7]1 year ago
8 0

There is a tension of 7,019.4 N on the horizontal rope.

The pulling force that travels axially along a rod's ends, a string, a cable, a chain, or another similar device is known as tension.

The action-reaction pair of forces that are acting at the ends of the element are also known as tension.

The tension is measured in Newtons. On the horizontal rope, there is tension.

The following formula is used to determine the horizontal rope's tension:

Utilize the torque concept.

Mg (L/2) sin + mg M + 2mg sin/cos = T (M + 2m) L sin = T(L/2) cos 660 g tan = T let (This value should be included in the question)

(M + 2m)

GTAN=TTAN= (74.9 + 2 x 122) (9.8) (tan 66)

T = 7,019.4 N The tension in is 7,019.4 N.

The complete question is - An object with a mass of m = 122 kg is suspended by a rope from the end of a uniform boom with a mass of M = 74.9 kg and a length of l = 8.77 m. The end of the boom is supported by another rope which is horizontal and attached to the wall as shown in the figure.

Calculate the tension in the horizontal rope. (The horizontal and the vertical ropes are not connected to each other. They are both independently attached to the end of the boom.)

Learn more about Tension here-

brainly.com/question/6359509

#SPJ4

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Explanation:

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How fast can the 140 a current through a 0.200 h inductor be shut off if the induced emf cannot exceed 80.0 v?
Vesna [10]
Recall that to compute for the emf of a circuit given current and inductance, we must recall that 

emf = - M \frac{\Delta I }{\Delta t}

where I is the current (A), M is the mutual inductance (h), and t is the time (ms). Since the current must not exceed 80.0 V, we have

80.0 \geq 0.200(\frac{140}{t})
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From this, we see that it must take at least 0.35 ms so it doesn't exceed 80 V.
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7 0
3 years ago
the roque requried to turn the crank on an ice cream maker is 4.50 N.m how much work does it take to turn the crank through 300
Alexus [3.1K]

Answer:

the work required to turn the crank at the given revolutions is 8,483.4 J

Explanation:

Given;

torque required to turn the crank, T = 4.50 N.m

number of revolutions, = 300 turns

The work required to turn the crank is given as;

W = 2πT

W = 2 x 3.142 x 4.5

W = 28.278 J

1 revolution = 28.278 J

300 revlotions = ?

= 300 x 28.278 J

= 8,483.4 J

Therefore, the work required to turn the crank at the given revolutions is 8,483.4 J

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S.I unit for moment of inertia of a fly wheel​
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A physics student stands on a cliff overlooking a lake and decides to throw a softball to her friends in the water below. She th
aliina [53]

Answer:

58.5 m

Explanation:

First of all, we need to find the total time the ball takes to reach the water. This can be done by looking at the vertical motion only.

The initial vertical velocity of the ball is

u_y = u sin \theta

where

u = 21.5 m/s is the initial speed

\theta=33.5^{\circ} is the angle

Substituting,

u_y = (21.5) sin 33.5^{\circ} =11.9 m/s

The vertical position of the ball at time t is given by

y = h + u_y t + \frac{1}{2}gt^2

where

h = 13.5 m is the initial heigth

g = -9.8 m/s^2 is the acceleration of gravity (negative sign because it points downward)

The ball reaches the water when y = 0, so

0 = h + u_yt +\frac{1}{2}gt^2\\0 = 13.5 +11.9 t - 4.9t^2

Which gives two solutions: t = 3.27 s and t = -0.84 s. We discard the negative solution since it is meaningless.

The horizontal velocity of the ball is

u_y = u cos \theta = (21.5) cos 33.5^{\circ} =17.9 m/s

And since the motion along the horizontal direction is a uniform motion, we can find the horizontal distance travelled by the ball as follows:

d= u_x t = (17.9)(3.27)=58.5 m

3 0
3 years ago
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