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4 years ago

A star produces 2x10^26 watts. how much energy does it lose every minutes

Physics

1 answer:

Step2247 [10]4 years ago

7 0

Answer:

Energy loss per minute will be $120\times 10^{26}j$

Explanation:

We have given the star produces power of $2\times 10^{26}W$

We know that 1 W = 1 J/sec

So $2\times 10^{26}W=2\times 10^{26}J/sec$

Given time = 1 minute = 60 sec

So the energy loss per minute $=2\times 10^{26}\times 60=120\times 10^{26}j$

We multiply with 60 we have to calculate energy loss per minute

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2. If a rock fell down a cliff and hit the bottom of the ravine at 4 seconds, how fast was the rock

Iteru [2.4K]

Answer: -39.2 m/s or 39.2 m/s directed downwards

Explanation:

This situation is a good example of Free Fall, where the main condition is that the initial velocity must be zero $V_{o}=0$ , and the acceleration is constant (acceleration due gravity).

So, in order to calculate the final velocity $V$ of the rock just at the moment it hitsthe bottom of the cliff, we will use the following equation:

$V={V_{o}}^{2}+gt$

Where:

$g=-9.8 m/s^{2}$ is the acceleration due gravity (directed downwards)

$t=4 s$ is the time it takes to the rock to fall down the cliff

$V=(-9.8 m/s^{2})(4 s)$

$V=-39.2 m/s$ This is the rock's final velocity and its negative sign indicates it is directed downwards

6 0

4 years ago

Read 2 more answers

Which of the following is the correct relationship among the acceleration, velocity, and position?

Damm [24]

Answer:1

Explanation:

s=displacement

v=velocity of particle

a=acceleration of particle

acceleration can be written as rate of change of velocity

so $a=\frac{\mathrm{d} v}{\mathrm{d} t}$

multiply and divide by $ds$

$a=\frac{\mathrm{d} v}{\mathrm{d} t}\times \frac{ds}{ds}$

$a=\frac{\mathrm{d} v}{\mathrm{d} s}\times \frac{\mathrm{d} s}{\mathrm{d} t}$

$a=v\frac{\mathrm{d} v}{\mathrm{d} s}$

$ads=vdv$

option 1 is correct

5 0

3 years ago

Read 2 more answers

If a ball starts with the velocity of 2.0m/s and accelerates with a constant rate of 0.50m/s squared for 2.5s what is the balls

baherus [9]

Acceleration can be any change in speed, increasing or decreasing.
You haven't said whether the ball is speeding up or slowing down.

If its acceleration is positive ... speed is increasing ... then in 2.5 seconds,
it GAINS (0.5 m/s² x 2.5 sec) = 2.5 m/s of speed. Added to its initial
speed of 2.0 m/s, it ends up moving at 4.5 m/s.

If its acceleration is negative ... speed is decreasing ... then in 2.5 seconds,
it LOSES (0.5 m/s² x 2.5 sec) = 2.5 m/s of speed. Added to its initial
speed of 2.0 m/s, it ends up moving at -0.5 m/s. That means that it ends up
moving in the opposite direction compared to its direction at the beginning of
the change.

7 0

3 years ago

A vw bug is driving north on a straight two lane road at a constant 54 mph and chevy impala south at 47 on the same road (but di

mario62 [17]

Velocity of vw bug is given as

$v_1 = 54 mpH$ towards north