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3 years ago

A star produces 2x10^26 watts. how much energy does it lose every minutes

Physics

1 answer:

Step2247 [10]3 years ago

7 0

Answer:

Energy loss per minute will be $120\times 10^{26}j$

Explanation:

We have given the star produces power of $2\times 10^{26}W$

We know that 1 W = 1 J/sec

So $2\times 10^{26}W=2\times 10^{26}J/sec$

Given time = 1 minute = 60 sec

So the energy loss per minute $=2\times 10^{26}\times 60=120\times 10^{26}j$

We multiply with 60 we have to calculate energy loss per minute

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A particle accelerator fires a proton into a region with a magnetic field that points in the x-direction. (a) If the proton is m

iVinArrow [24]

Answer:

The magnitude of the magnetic field will act in a direction towards me.

Explanation:

When a charged particle enters a magnetic field, it is deflected. The direction of travel of the particle is deflected, but the kinetic energy of the particle is not affected. The force experienced by a charged particle as it enters a magnetic field that acts perpendicular to the path of the velocity of the particle, will produce a force that is perpendicular to both the direction of travel of the particle and the direction of the magnetic field. In this case, the proton moves in the y-direction, the magnetic field is in the x-direction, therefore the force experienced by the particle will be towards me.

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3 years ago

Ned tightens a bolt in his car engine by exerting 15 N of force on his wrench at a distance of 0.45m from the fulcrum. How much

____ [38]

Answer:

$T = 6.75\,N\cdot m$

Explanation:

Vectorially speaking, torque is the cross product between force and distance from fulcrum. Its magnitude is equal to the following expression:

$T = F\cdot r \cdot \sin \theta$

$T = F_{\bot} \cdot r$

Let assume that force is perpendicular to the distance from the fulcrum. So, the torque needed to turn the bolt is:

$T = (15\,N)\cdot (0.45\,m)$

$T = 6.75\,N\cdot m$

8 0

3 years ago

hich of the following statements are true for magnetic force acting on a current-carrying wire in a uniform magnetic field?Check

leonid [27]

Explanation:

The magnetic force acting on a current carrying wire in a uniform magnetic field is given by :

$F=I(L\times B)$

$F=ILB\ sin\theta$

Where

$\theta$ is the angle between length and the magnetic field

The magnetic force is perpendicular to both current and magnetic field. It is maximum when it is perpendicular to both current and magnetic field.

So, the correct options are :

The magnetic force on the current-carrying wire is strongest when the current is perpendicular to the magnetic field lines.
.The direction of the magnetic force acting on a current-carrying wire in a uniform magnetic field is perpendicular to the direction of the field.
The direction of the magnetic force acting on a current-carrying wire in a uniform magnetic field is perpendicular to the direction of the current.

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3 years ago

Alligators and other reptiles don't use enough metabolic energy to keep their body temperatures constant. They cool off at night

ANTONII [103]

Answer:

Explanation:

Amount of heat required can be found from the following relation

Q = mcΔT

m is mass of the body , c is specific heat and ΔTis rise in temperature .

Here m = 300 kg

c = 3350 J /kg k

ΔT = 30 - 25

= 5 °C

Putting the values in the expression above

Q = 300 x 3350 x 5

= 5025000 J

Rate at which energy is absorbed = 1200 J /s

Time required

= 5025000 / 1200

= 4187.5 S

= 69.8 minute

= 1 hour 9.8 mimutes.

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3 years ago

A ball is dropped from a height of 180m- Calculate the velocity of the ball when it strikes the ground

gayaneshka [121]

Answer:

6s , 60mls

Explanation:

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6 0

3 years ago

Read 2 more answers