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SpyIntel [72]
4 years ago
9

A star produces 2x10^26 watts. how much energy does it lose every minutes

Physics
1 answer:
Step2247 [10]4 years ago
7 0

Answer:

Energy loss per minute will be 120\times 10^{26}j

Explanation:

We have given the star produces power of 2\times 10^{26}W

We know that 1 W = 1 J/sec

So 2\times 10^{26}W=2\times 10^{26}J/sec

Given time = 1 minute = 60 sec

So the energy loss per minute =2\times 10^{26}\times 60=120\times 10^{26}j

We multiply with 60 we have to calculate energy loss per minute

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2. If a rock fell down a cliff and hit the bottom of the ravine at 4 seconds, how fast was the rock
Iteru [2.4K]

Answer: -39.2 m/s or 39.2 m/s directed downwards

Explanation:

This situation is a good example of Free Fall, where the main condition is that the initial velocity must be zero V_{o}=0, and the acceleration is constant (acceleration due gravity).

So, in order to calculate the final velocity V of the rock just at the moment it hitsthe bottom of the cliff, we will use the following equation:

V={V_{o}}^{2}+gt

Where:

g=-9.8 m/s^{2} is the acceleration due gravity (directed downwards)

t=4 s is the time it takes to the rock to fall down the cliff

V=(-9.8 m/s^{2})(4 s)

V=-39.2 m/s This is the rock's final velocity and its negative sign indicates it is directed downwards

6 0
4 years ago
Read 2 more answers
Which of the following is the correct relationship among the acceleration, velocity, and position?
Damm [24]

Answer:1

Explanation:

If

s=displacement

v=velocity of particle

a=acceleration of particle

acceleration can be written as rate of change of velocity

so a=\frac{\mathrm{d} v}{\mathrm{d} t}

multiply and divide by ds

a=\frac{\mathrm{d} v}{\mathrm{d} t}\times \frac{ds}{ds}

a=\frac{\mathrm{d} v}{\mathrm{d} s}\times \frac{\mathrm{d} s}{\mathrm{d} t}

a=v\frac{\mathrm{d} v}{\mathrm{d} s}

ads=vdv

option 1 is correct

5 0
3 years ago
Read 2 more answers
If a ball starts with the velocity of 2.0m/s and accelerates with a constant rate of 0.50m/s squared for 2.5s what is the balls
baherus [9]

Acceleration can be any change in speed, increasing or decreasing.
You haven't said whether the ball is speeding up or slowing down.

If its acceleration is positive ... speed is increasing ... then in 2.5 seconds,
it GAINS (0.5 m/s² x 2.5 sec) = 2.5 m/s of speed.  Added to its initial
speed of 2.0 m/s, it ends up moving at 4.5 m/s.

If its acceleration is negative ... speed is decreasing ... then in 2.5 seconds,
it LOSES (0.5 m/s² x 2.5 sec) = 2.5 m/s of speed.  Added to its initial
speed of 2.0 m/s, it ends up moving at  -0.5 m/s.  That means that it ends up
moving in the opposite direction compared to its direction at the beginning of
the change.

7 0
3 years ago
A vw bug is driving north on a straight two lane road at a constant 54 mph and chevy impala south at 47 on the same road (but di
mario62 [17]

Velocity of vw bug is given as

v_1 = 54 mpH towards north

velocity of imphala is given as

v_2 = 47 mph towards south

now we need to find velocity of imphala relative to bug

v_{21} = v_2 - v_1

v_{21} = 47 - (-54) = 101 mpH

so the speed is 101 mpH towards south so correct option is C

5 0
3 years ago
What is the name of the british scientist credited with discovering cathode rays?
elena-14-01-66 [18.8K]
<span> </span>J. J. <span>Thomson discovered cathode rays</span>
5 0
3 years ago
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