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Montano1993 [528]
3 years ago
14

Consider the cantilever-beam Wheatstone bridge system that has four strain gages (two in compression and two in tension). Which

of the following statements is not true: (a) the change in resistance in each gage is proportional to the applied force, (b) temperature and torsional effects are automatically compensated for by the bridge, (c) the longitudinal (axial) strain in the beam is proportional to the output voltage of the bridge, (d) a downward force on the beam causes an increase in the resistance of a strain gage placed on its lower (under) side. Final Ans: (d) Compression on a lower side gage causes an increase in its resistance.
Physics
1 answer:
Ivahew [28]3 years ago
3 0

Answer:  (b) temperature and torsional effects are automatically compensated for by the bridge,

Explanation:

As can be seen, strain gages 1 and 4 are on top of the beam and strain gages 2 and 3 are on the bottom of

the beam. Therefore strain gages 1 and 4 experience a tensile strain (are stretched) and strain gages 2

and 3 experience a compressive strain. If the relationship between strain and resistance is linear, then

under some load F the changes in resistance will be

R1= R1 + dR1

R4= R4 + dR4

tensile(4)and

R ¢2= R2 -dR2

R ¢3= R3 -dR3

compressive. (5)

when the four strain gages have an equal nominal

resistance (i.e., R1 = R2 = R3 = R4 = R) then the deflection method Wheatstone bridge equation reduces to the linear equation

Using known weights, a calibration curve can be established that relates the weight W to the output

voltage on a digital meter Eo,

Eo= a0 + a1W , (4)

where a0 and a1 are some constants. Once an unknown weight is known, an unknown mass or density

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n 38 g rifle bullet traveling at 410 m/s buries itself in a 4.2 kg pendulum hanging on a 2.8 m long string, which makes the pend
Kitty [74]

Answer:

68cm

Explanation:

You can solve this problem by using the momentum conservation and energy conservation. By using the conservation of the momentum you get

p_f=p_i\\mv_1+Mv_2=(m+M)v

m: mass of the bullet

M: mass of the pendulum

v1: velocity of the bullet = 410m/s

v2: velocity of the pendulum =0m/s

v: velocity of both bullet ad pendulum joint

By replacing you can find v:

(0.038kg)(410m/s)+0=(0.038kg+4.2kg)v\\\\v=3.67\frac{m}{s}

this value of v is used as the velocity of the total kinetic energy of the block of pendulum and bullet. This energy equals the potential energy for the maximum height reached by the block:

E_{fp}=E_{ki}\\\\(m+M)gh=\frac{1}{2}mv^2

g: 9.8/s^2

h: height

By doing h the subject of the equation and replacing you obtain:

(0.038kg+4.2kg)(9.8m/s^2)h=\frac{1}{2}(0.038kg+4.2kg)(3.67m/s)^2\\\\h=0.68m

hence, the heigth is 68cm

4 0
3 years ago
A binary star system consists of two stars of masses m1 and m2. The stars, which gravitationally attract each other, revolve aro
mote1985 [20]

Answer: a_{2}=\frac{m_{1}}{m_{2}} a_{1}

Explanation:

The rest of the question is below:

Find a2, the magnitude of the centripetal acceleration of the star with mass m2.

Assuming both stars are describing a uniform circular motion, their acceleration vector is directed towards the center of mass of the system (that's why it's called centripetal acceleration).  

Now, according to Newton's 2nd law, the force F is directly proportional and in the same direction as the acceleration.

For m_{1}:

F_{1}=m_{1}a_{1}  

For m_{2}:

F_{2}=m_{2}a_{2}  

If the centripetal force is the same for both stars:

F_{1}=F_{2}  

m_{1}a_{1}=m_{2}a_{2}  

Isolating a_{2}:

a_{2}=\frac{m_{1}}{m_{2}} a_{1}

8 0
3 years ago
A turntable has an angular velocity of 3.5 rad/s. A dust bunny is on the disk of the turntable at a distance of 0.2m from the ce
diamong [38]

Answer:

E. 0.25

Explanation:

Given that

Angular speed ω = 3.5 rad/s

Distance ,r= 0.2 m

Lets take mass of dust bunny = m

We know that

Radial force F = m ω² r

The friction force on the dust bunny Fr

Fr= μ m g

To getting slung off  dust bunny from disk

m ω² r =  μ m g

ω² r =  μ  g

3.5²  x 0.2 =  μ x 10                        ( take g =10 m/s²)

μ = 0.245

μ = 0.25

Therefore answer is E

E. 0.25

3 0
3 years ago
If a sound wave is produced with a wavelength of 1.04m what is the waves frequency
dmitriy555 [2]
You should just ask the wave 
5 0
3 years ago
Two metal balls are the same size, but one weighs twice as much as the other. The balls are dropped from the top of a two story
seropon [69]

The time taken by the metal balls of the same size but different weight, to reach the ground will be the same.

Reason behind:

Two metal balls are the same size, but one weighs twice as much as the other. The balls are dropped from the top of a two-story building at the same instant of time. It is required to find the time taken by the balls to reach the ground.

In free fall, all objects experience the same acceleration owing to gravity when they are close to the earth.

g=9.8 \text{ m/s}^2 is the measure of gravitational acceleration.

Because of this, the two metal balls are the same size but have different masses. The air resistance for both balls will be the same due to their similar sizes. Let, g' be the acceleration in the presence of air resistance. The balls are both discharged at once.

From a height of h, both balls descend due to gravity G'.

Therefore, the time taken by both balls is:

\begin{aligned}&s=u t+\frac{1}{2} g t^{2} \\&u=0, s=h \\&t=\sqrt{\frac{2 h}{g}}\end{aligned}

Therefore, the time is independent of mass. Thus the time taken by both the balls, will be about the same.

Learn more about time taken by metal ball to reach the ground here,

brainly.com/question/22719691

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4 0
2 years ago
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