Answer:
what was the answer
Explanation:
im taking the quiz and could use some help
Answer:
The deceleration is 0.18 m/s²
Explanation:
Hi there!
Using Newton´s second law, we can calculate the deceleration:
∑F = m · a
Where:
∑F = the sum of all forces in a given direction.
m = mass of the object.
a = acceleration.
Solving for a:
∑F/m = a
The only force acting on the meteor is the applied force of 8.6 N. So, the acceleration will be:
8.6 N / 48.9 kg = a
a = 0.18 m/s²
The deceleration is 0.18 m/s² or, in other words, the acceleration is -0.18 m/s²
Have a nice day!
Answer:
292.3254055 W/m²
469.26267 V/m
Explanation:
P = Power of bulb = 90 W
d = Diameter of bulb = 7 cm
r = Radius = 
= Permittivity of free space = 
c = Speed of light = 
The intensity is given by
5% of this energy goes to the visible light so the intensity is
The visible light intensity at the surface of the bulb is 292.3254055 W/m²
Energy density of the wave is
Energy density is also given by
The amplitude of the electric field at this surface is 469.26267 V/m
Amplitude of a magnetic field is given by
The amplitude of the magnetic field at this surface is
Answer:
True
Explanation:
The angular momentum around the center of the planet and the total mechanical energy will be preserved irrespective of whether the object moves from large R to small R. But on the other hand the kinetic energy of the planet will not be conserved because it can change from kinetic energy to potential energy.
Therefore the given statement is True.
