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Lady bird [3.3K]
3 years ago
12

6) A map in a ship’s log gives directions to the location of a buried treasure. The starting location is an old oak tree. Accord

ing to the map, the treasure’s location is found by proceeding 20 paces north from the oak tree and then 30 paces northwest. At this location, an iron pin is sunk in the ground. From the iron pin, walk 10 paces south and dig. How far (in paces) from the oak tree is the spot at which digging occurs?
Physics
1 answer:
kiruha [24]3 years ago
4 0

Answer:

Sorry cant find the answer but i hope you got it right and if you didn't you'll still do great. :)

Explanation:

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A long iron bar lies along the x-axis and has current of I = 16.4 A running through it in the +x-direction. The bar is in the pr
Gre4nikov [31]

Answer:

B = 8.0487mT

Explanation:

To solve the exercise it is necessary to take into account the considerations of the Magnetic Force described by Faraday,

The magnetic force is given by the formula

F =BILsin\theta

Where,

B = Magnetic Field

I = Current

L = Length

\theta = Angle between the magnetic field and the velocity, for this case are perpendicular, then is 90 degrees

According to our data we have that

I = 16.4A

F = 0.132N/m

As we know our equation must be modificated to Force per length unit, that is

\frac{F}{L} = BI sin(90)

Replacing the values we have that

0.132 = 16.4 (1) B

Solving for B,

B = \frac{0.132}{16.4}

B = 8.0487mT

8 0
3 years ago
Two banked curves have the same radius. Curve A is banked at 12.7 °, and curve B is banked at an angle of 15.1°. A car can trave
Elina [12.6K]

Answer:

20.88 m/s

Explanation:

Curve A:

theta = 12.7, vA = 19.1 m/s

Curve B:

Theta = 15.1 degree

Let the speed is v.

By the use of given formula

tanθ = v^2 / rg

For Curve A

tan 12.7 = (19.1)^2 / r g   ...... (1)

For Curve B

tan 15.1 = v^2 / r g       ......(2)

Divide equation (2) by equation (1), we get

tan 15.1 / tan 12.7  = v^2 / (19.1)^2

0.269 / 0.225 = v^2 / 364.81

v = 20.88 m/s

6 0
3 years ago
A toaster uses 1500 W of power when connected to a voltage of 120 V. What is the resistance
iVinArrow [24]

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Explanation:

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