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dem82 [27]
3 years ago
5

CH4 and CH3CH2CH3 have the lowest boiling points because they experience only \rm CH_4 and \rm CH_3CH_2CH_3 have the lowest boil

ing points because they experience only _____________, the effects of which increase with increasing ______., the effects of which increase with increasing \rm CH_4 and \rm CH_3CH_2CH_3 have the lowest boiling points because they experience only _______________, the effects of which increase with increasing _____________..
Chemistry
1 answer:
ki77a [65]3 years ago
6 0

Answer:

Dispersion forces

Relative molecular mass

Explanation:

Alkanes experience only dispersion forces. Dispersion forces increase with increasevin the relative molecular mass of the compounds. Hence a higher relative molecular mass implies greater dispersion forces and a greater boiling point.

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Which statement best describes comparative and descriptive investigations?
olasank [31]

Answer:

they both include a question, procedure and conclusion.

Explanation:

7 0
3 years ago
When 7.00 g of hydrogen react with 70.0 g of nitrogen, hydrogen is considered the limiting reactant because:
noname [10]

7.5 mol of hydrogen would be needed to consume the available nitrogen.

Explanation:

When hydrogen reacts with nitrogen, ammonia is formed as shown below;

3H₂ (g) + N₂ (g) → 2NH₃ (g)

As seen from the equation, every 3 moles of H₂ react with a mole of N₂ to form 2 moles of NH₃.

The limiting factor in a chemical reaction is the reactant that gets depleted first.

Because the molar mass of nitrogen gas is approximately 28g/mol, 70g of nitrogen gas would be 2.5 moles.

The reaction ratio of nitrogen to hydrogen in the reaction is 1 : 3. The reaction would require 2.5 * 3 (7.5) moles of hydrogen for a complete reaction.

However since there are only 7g on hydrogen, (Remember 1 mole of H₂ is approximately 2g), the available moles of H₂ is 7 / 2 = 3.5

3.5 moles fall short of the 7.5 moles of H₂ required for a complete reaction. H₂ gets depleted first before N₂.  The reaction would require 4 more moles of H₂.

6 0
3 years ago
What is a promblem based on charles' law?
LUCKY_DIMON [66]

Answer:

You will never know the exact volume with charles law

Explanation:

Doubling the temperature of gas doubles its volume, so long as the pressure and quantity of the gas are unchanged.

5 0
4 years ago
Read 2 more answers
What parts are present in every chemical equation?
77julia77 [94]
I believe it’s

The reactants

The products

And the Arrow indicating the direction of the chemical reaction
3 0
3 years ago
The combustion of propane may be described by the chemical equation C 3 H 8 ( g ) + 5 O 2 ( g ) ⟶ 3 CO 2 ( g ) + 4 H 2 O ( g ) C
Kipish [7]

Answer: 72 grams of O_2(g) are needed to completely burn 19.7 g C_3H_8(g)

Explanation:

According to avogadro's law, 1 mole of every substance weighs equal to molecular mass and contains avogadro's number 6.023\times 10^{23} of particles.

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Putting in the values we get:

\text{Number of moles}=\frac{19.7g}{44g/mol}=0.45moles

C_3H_8(g)+5O_2(g)\rightarrow 3CO_2(g)+4H_2O(g)

According to stoichiometry:

1 mole of C_3H_8 requires 5 moles of oxygen

0.45 moles of C_3H_8 require= \frac{5}{1}\times 0.45=2.25 moles of oxygen

Mass of O_2=moles\times {\text {Molar mass}}=2.25\times 32=72g

72 grams of O_2(g) are needed to completely burn 19.7 g C_3H_8(g)

7 0
3 years ago
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