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GrogVix [38]
4 years ago
14

What do the length of the cord and gravity determine for a pendulum?

Physics
2 answers:
barxatty [35]4 years ago
5 0
Period is the correct answer
kap26 [50]4 years ago
5 0
The correct answer is period.
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A 70 cm diameter wheel accelerates uniformly about its center from 130 rpm to 280 rpm in 4.0 s. determine (a) its angular accele
lina2011 [118]

Part a)

as we know that angular speed is given as

\omega = 2 \pi f

here we have

f_2 = 280 rpm = 4.67Hz

f_1 = 130 rpm = 2.17 Hz

now for angular acceleration we have

\alpha = \frac{\omega_f - \omega_i}{\Delta t}

\alpha = \frac{2\pi(f_2 - f_1)}{\Delta t}

\alpha = \frac{2\pi(4.67 - 2.17)}{4}

\alpha = 3.93 rad/s^2

Part b)

angular speed of the wheel after t = 2 s

\omega_f = \omega_i + \alpha t

\omega_f = 2\pi (2.17) + 3.93 (2)

\omega_f = 21.5 rad/s

now we have

tangential acceleration

a_t = r \alpha

a_t = 0.70(3.93) = 2.75 m/s^2

radial acceleration will be

a_r = \omega^2 r

a_r = (21.5)^2(0.70) = 323.6 m/s^2

3 0
3 years ago
At what age is a child likely to learn to sit up without support?
Gemiola [76]

Answer by YourHope:


Hi! ^-^


At what age is a child likely to learn to sit up without support?


I would say Five months if you position the child but Nine months for the baby to sit up by themselves! So the answer is Nine months!


Have a BEAUTIFUL day~

4 0
3 years ago
What mass of steam at 100°C must be mixed with 490 g of ice at its melting point, in a thermally insulated container, to produce
sukhopar [10]

Answer:

the mass of steam at 100°C must be mixed is 150 g

Explanation:

given information:

ice's mass, m_{i} = 490 g = 0.49 kg

steam temperature, T = 100°C

liquid water temperature, T = 89.0°C

specific heat of water, c_{w} = 4186 J/kg.K = 4.186 kJ/kg.K

latent heat of fusion, L_{f} = 333 kJ/kg

latent heat of vaporization, L_{v} = 2256 kJ/kg

first, we calculate the heat of melted ice to water

Q₁ = m_{i} L_{f}

where

Q = heat

m_{i} = mass of the ice

L_{f}  = latent heat of fusion

thus,

Q₁ = m_{i} L_{f}

    = 0.49 x 333

    = 163.17 kJ

then, the heat needed to increase the temperature of water to 89.0°C

Q₂ = m_{i} c_{w} (89 - 0), the temperature of ice is 0°C

c_{w} = specific heat of water

so,

Q₂ = m_{i} c_{w} (89 - 0)

     = 0.49 x 4.186 x 89

     = 182.55 kJ

so, the heat absorbed by the ice is

Q = Q₁ + Q₂

   = 163.17 + 182.55

   = 345.72 kJ

the temperature of the steam is 100°C, so the mass of the steam is

Q = m_{s}L_{v}  +  m_{s}c_{w} (100 - 89)

Q = m_{s}(L_{v}  +  c_{w} (11))

m_{s} = Q/ [L_{v}  +  c_{w} (11)]

      = 345.72/ [2256 + (4.186 x 11)]

      = 0.15 kg

      = 150 g

5 0
3 years ago
A block of iron at 33.0°C has mass 2.30 kg. If 3.50×104 J of heat are transferred to the block, what is its resulting temperatur
spayn [35]

Answer:

66.8°C

Explanation:

dQ = m*cp*dT where:

m = mass of block

cp = specific heat of iron

dT = temperature change

-------

dQ = 3.5 10^4 J

cp = 0.45 Kj / Kg = 450 J / Kg

3.5 10^4 = 2.3 * 450 * dt-----dt = 35000 / 450 * 2.3 = 33.8 °

-------

Final temperature = 33 + 33.8 = 66.8 °C

3 0
3 years ago
What do we call the certain electrons that are able to sometimes wander<br> away or be shared? *
Natalka [10]

Answer:

compond

Explanation:

5 0
3 years ago
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