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3 years ago

Which statement is true?

Physics

2 answers:

ratelena [41]3 years ago

8 0

Statement ' A ' is true.

sveta [45]3 years ago

4 0

Answer:

A.Speed is a scalar quantity and velocity is a vector quantity.

TRUE

Speed is the ratio of distance and time while velocity is the ratio of displacement and time

B.Speed and velocity are both scalar quantities.

FALSE

velocity is a vector quantity and it is ratio of displacement and time

C.Speed and velocity are both vector quantities.

FALSE

Speed is not a vector quantity but it is a scalar quantity

D.Speed is a vector quantity and velocity is a scalar quantity.

FALSE

Speed is scalar as it depends on distance while velocity is a vector which depends on displacement

E.Speed and velocity are neither a scalar quantity nor a vector quantity.

FALSE

Speed is scalar while velocity is vector

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Kinetic friction is the frictional force needed to start an object at rest into

Ket [755]

Answer:

b.false i think

Explanation:

i hope i am correct and helps you

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3 years ago

ou have just moved into a new apartment and are trying to arrange your bedroom. You would like to move your dresser of weight 3,

Dimas [21]

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In Physics, "Work" is the product of Force times Distance.

Since the dresser hasn't budged yet, the Distahce is zero. So no matter how great the Force may be, it's multiplied by zero, so the Work is zero.

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4 years ago

A rocket in orbit just above the atmosphere is moving in uniform circular motion. The radius of the circle in which it moves is

Zinaida [17]

Centripetal acceleration is given by the formula

$a_{cen}= \frac{v^2}{r}$

Since we know the value of the acceleration is 9.8 m/s² and we know r, we can solve for the speed, which is the magnitude of v. Note the value of a is just the acceleration due to gravity, which is what makes the rocket orbit and not fly off into space.

$9.8 \frac{m}{s^2}=\frac{v^2}{6.381 \times 10^6m} \\ \\ 9.8 \frac{m}{s^2} \times 6.381 \times 10^6m=v^2 \\ \\ v= \sqrt{9.8 \frac{m}{s^2} \times 6.381 \times 10^6m} =24755 \frac{m}{s}$

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3 years ago

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Ne4ueva [31]

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3 years ago

Let's apply Snell's law to the refraction of light across a water–air interface. Suppose you kneel beside the fishpond in your b

Nataliya [291]

Answer:

The angle of refraction is 41.68°.

Explanation:

The refractive index for water is $n_2 = 1.333$ , and for air $n_1 = 1.00$ : the angle of light with the normal is $90^o-60^o = 30^o$ ; therefore Snell's law gives