This problem can be solved using a kinematic equation. For this case, the following equation is useful:
v_final = v_initial + at
where,
v_final = final velocity of the nail
v_initial = initial velocity of the nail
a = acceleration due to gravity = 9.8 m/s^2
t = time
First, we determine the time it takes for the nail to hit the ground. We know that the initial velocity is 0 m/s since the nail was only dropped. It has a final velocity of 26 m/s. We substitute these values to the equation and solve for t:
26 = 0 + 9.8*t
t = 26/9.8 = 2.6531 s
The problem asks the velocity of the nail at t = 1 second. We then subtract 1 second from the total time 2.6531 with v_final as unknown.
v_final = 0 + 9.8(2.6531-1) = 16.2004 m/s.
Thus, the nail was traveling at a speed of 16. 2004 m/s, 1 second before it hit the ground.
So, the time that taken for the astronaut to fall to the surface of the moon is <u>2.5 s.</u>
<h3>Introduction</h3>
Hi ! In this question, I will help you. In this question, you will learn about the fall time of the free fall motion. Free fall is a downward vertical motion without being preceded by an initial velocity. When moving in free fall, the time required can be calculated by the following equation:



With the following condition :
- t = interval of the time (s)
- h = height or any other displacement at vertical line (m)
- g = acceleration of the gravity (m/s²)
<h3>Problem Solving</h3>
We know that :
- h = height = 5.00 m
- g = acceleration of the gravity = 1.6 m/s²
What was asked :
- t = interval of the time = ... s
Step by step :




<h3>Conclusion</h3>
So, the time that taken for the astronaut to fall to the surface of the moon is 2.5 s.
<h3>See More</h3>
By definition, the refractive index is
n = c/v
where c = 3 x 10⁸ m/s, the speed of light in vacuum
v = the speed of light in the medium (the liquid).
The frequency of the light source is
f = (3 x 10⁸ m/s)/(495 x 10⁻⁹ m) = 6.0606 x 10¹⁴ Hz
Because the wavelength in the liquid is 434 nm = 434 x 10⁻⁹ m,
v = (6.0606 x 10¹⁴ 1/s)*(434 x 10⁻⁹ m) = 2.6303 x 10⁸ m/s
The refractive index is (3 x 10⁸)/(2.6303 x 10⁸) = 1.1406
Answer: a. 1.14
Solution:
<span>Starting with </span>g <span>equal to (1/0.6), solve for v.</span>
<span>v = 0.8c = 2.4E8 m/s</span>