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bonufazy [111]
2 years ago
11

Which is true about the pressure of a fluid at a specific depth? A. It depends on the surface area of the fluid. B. It is exerte

d only in the downward direction. C. It depends only on the type of fluid. D. It varies with the total volume of the fluid.
Physics
1 answer:
Dahasolnce [82]2 years ago
4 0

Answer:

c) depends only on the type of fluid

Explanation:

The pressure of a fluid at a specific depth is given by:

where

is the density of the fluid

g is the gravitational acceleration

h is the depth

We see that for a given depth h, the pressure of the fluid depends only on its density, so only on the type of fluid. Therefore, the correct choice is

a) depends only on the type of fluid

The other choices are wrong because:

b) the pressure is exerted in every direction

c) the pressure does not depend on the total volume of the fluid, but only on the depth h

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That's 139 mph !  Wow !

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What is the action force and reaction force of two bumper cars collide
raketka [301]
<span>action is the one car hitting the other, reaction is the other car being pushed away</span>
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Determine the angular speed, in rad/s of:
ryzh [129]

Answer:

Explanation:

A. The earth about its axis:

The earth makes one revolution in 24 hours. to know the number of revolutions per second it makes, we need to convert hours to seconds and the revolution to rad.

\frac{1 rev}{24hours}\times \frac{1 hr}{3600s}\times \frac{2\pi}{1}= 7.27 \times10^-5 rad/s

B. The minute hand of the clock makes one revolution in 60 minutes

To convert this to rad per second, we have

\frac{1 rev}{60mins}\times \frac{1 min}{60s}\times \frac{2\pi}{1}= 1.745 \times10^-3rad/s

C. The hour hand of  a clock completes one revolution in 12 hours

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D. an egg beater turning at 300 rpm.

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6 0
2 years ago
For general projectile motion, the horizontal component of a projectile's velocity aSelect one:O a. continuously increases.O b.
liubo4ka [24]

ANSWER:

d. remains a non-zero constant.

STEP-BY-STEP EXPLANATION:

If we consider that there is no air resistance and that the horizontal component would be at x, the velocity remains a non-zero constant

3 0
1 year ago
A box has a weight of 150 N and is being pulled across a horizontal floor by a force that has a magnitude of 110 N. The pulling
ivann1987 [24]

Answer:

42.99°

Explanation:

F_h = Kinetic friction force

F_{\theta} = Pulling force at angle \theta

N_h = Weight of the box = 150 N

Kinetic friction force

F_h=\muN_h

Pulling force at angle \theta

F_{\theta}=\muN_{\theta}

N = Pulling force

According to question

\frac{F_h}{F_{\theta}}=\frac{2}{1}\\\Rightarrow \frac{\muN_h}{\muN_{\theta}}=2\\\Rightarrow \frac{N_h}{N_{\theta}}=2\\\Rightarrow N_{\theta}=\frac{N_h}{2}\\\Rightarrow N_{\theta}=\frac{150}{2}\\\Rightarrow N_{\theta}=75\ N

Applying Newton's second law in the vertical direction we get

N_h-Nsin\theta=N_{\theta}\\\Rightarrow 150-110sin\theta=75\\\Rightarrow \theta=sin^{-1}\frac{75}{110}\\\Rightarrow \theta=42.99\ ^{\circ}

The angle is 42.99°

8 0
3 years ago
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