Answer: All of them are true
Where is the chooses for you question
The correct answer is light...
Answer:
a. sulfur difluoride SF₂
b. sulfur hexafluoride SF₆
c. sodium dihydrogen phosphate NaH₂PO₄
d. lithium nitride Li₃N
e. chromium(III) carbonate Cr₂(CO₃)₃
f. tin(II) fluoride SnF₂
g. ammonium acetate NH₄(CH₃COO)
h. ammonium hydrogen sulfate NH₄(HSO₄)
i. cobalt(III) nitrate Co(NO₃)₃
j. mercury(I) chloride Hg₂Cl₂
k. potassium chlorate KClO₃
l. sodium hydride NaH
Explanation:
The names give us information about the composition. First, we mention the cation and then the anion. In the formula, we follow the same order. Each part has a charge but the resulting compound is electrically neutral.
Answer:
-4.59°C
Explanation:
Let's see the formula for freezing point depression.
ΔT = Kf . m . i
ΔT = Freezing T° of pure solvent - Freezing T° of solution
Kf = Freezing constant. For water if 1.86°C/m
m = molality (moles of solute in 1kg of solvent)
i = Van't Hoff factor.
0°C - Freezing T° of solution = 1.86°C /m . 1.30m . 1.9
Freezing T° of solution = - (1.86°C /m . 1.30m . 1.9)
Freezing T° of solution = - (1.86°C/m . 1.30m . 1.9) → -4.59°C
NaCl → Na⁺ + Cl⁻