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Viktor [21]
3 years ago
9

How many acute, obtuse, and right angles are in this figure?

Mathematics
2 answers:
Eddi Din [679]3 years ago
6 0
There are 2 acute angles, 2 obtuse angles and 0 right angles.
Vinvika [58]3 years ago
4 0
2 acute and 2 obtuse and 0 right angles
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Justin is a teacher and takes home 76 papers to grade over the weekend. He can grade at a rate of 7 papers per hour. How many pa
allochka39001 [22]

Answer:

7.6

Step-by-step explanation:

I know math!!!!!!!!!!

3 0
3 years ago
Triangle abc is located on a coordinate plane angle c is at (1,2) the triangle is rotated counter clockwise 90° about the origin
sertanlavr [38]

After rotating a point C 90° counterclockwise about the origin the coordinates of C' would be (-2, 1)

In this question, we have been given a triangle ABC.

A point C is at (1, 2)

The triangle is rotated counter clockwise 90° about the origin.

We need to find the coordinates of C' which is image of vertex C  after rotation.

We know that, if we rotate a point 90° counterclockwise about the origin a point (x, y) becomes (-y, x).

Here C(1, 2) is rotated 90 degrees counterclockwise about the origin.

So, the coordinates of C' would be,

C' = (-2, 1)

Therefore, after rotating a point C 90° counterclockwise about the origin the coordinates of C' are (-2, 1)

Learn more about the rotation here:

brainly.com/question/2763408

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6 0
1 year ago
A piston rises to 5 cm and falls to 3 cm in such a way that it returns to the maximal height three times every two seconds. If w
sveticcg [70]

Answer:

(1 cm)cos3πt

Step-by-step explanation:

Since the piston starts at its maximal height and returns to its maximal height three times evert 2 seconds, it is modelled by a cosine functions, since a cosine function starts at its maximum point. So, its height h = Acos2πft

where A = amplitude of the oscillation and f = frequency of oscillation and t = time of propagation of oscillation.

Now, since the piston rises in such a way that it returns to the maximal height three times every two seconds, its frequency, f = number of oscillations/time taken for oscillation where number of oscillations = 3 and time taken for oscillations  = 2 s

So, f = 3/2 s =1.5 /s = 1.5 Hz

Also, since the the piston moves between 3 cm and 5 cm, the distance between its maximum displacement(crest) of 5 cm and minimum displacement(trough) of 3 cm is H = 5 cm - 3 cm = 2 cm. So its amplitude, A = H/2 = 2 cm/2 = 1 cm

h = Acos2πft

= (1 cm)cos2π(1.5Hz)t

= (1 cm)cos3πt

7 0
3 years ago
Round to the nearest hundred thousand 992,449
Lesechka [4]
The hundred thousand column is the 6th column so you look at the 5th number and round
9 rounds up to 0
but this also changes the 900000 to 1000000
so 992449 = 1000000 to nearest hundred thousand
8 0
3 years ago
Read 2 more answers
Three vertices of a parallelogram are shown in the figure below. Give the coordinates of the fourth vertex.
topjm [15]

Given:

The three vertices of a parallelogram are (-3,8), (4,5), (2,-5).

To find:

The fourth vertex of the parallelogram.

Solution:

Let the vertices of the parallelogram are A(-3,8), B(4,5), C(2,-5) and D(a,b).

We know that, diagonals of a parallelogram bisect each other. It means midpoints of both diagonals are same.

Midpoint formula:

Midpoint=\left(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\right)

Two diagonals of ABCD are AC and BD.

Midpoint of AC = Midpoint of BD

\left(\dfrac{-3+2}{2},\dfrac{8-5}{2}\right)=\left(\dfrac{4+a}{2},\dfrac{5+b}{2}\right)

\left(\dfrac{-1}{2},\dfrac{3}{2}\right)=\left(\dfrac{4+a}{2},\dfrac{5+b}{2}\right)

On comparing both sides, we get

\dfrac{4+a}{2}=\dfrac{-1}{2}

4+a=-1

a=-1-4

a=-5

And,

\dfrac{5+b}{2}=\dfrac{3}{2}

5+b=3

b=3-5

b=-2

Therefore, the coordinates of fourth vertex are (-5,-2).

3 0
2 years ago
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