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Nitella [24]
3 years ago
13

What volume will a balloon occupy at 1.0 atm, if the balloon has a volume of 7.6 l at 3.8 atm?

Chemistry
2 answers:
Olegator [25]3 years ago
8 0

<u>Answer:</u> The final volume of balloon is 28.88 L

<u>Explanation:</u>

To calculate the new volume, we use the equation given by Boyle's law. This law states that pressure is inversely proportional to the volume of the gas at constant temperature.

The equation given by this law is:

P_1V_1=P_2V_2

where,

P_1\text{ and }V_1 are initial pressure and volume.

P_2\text{ and }V_2 are final pressure and volume.

We are given:

P_1=3.8atm\\V_1=7.6L\\P_2=1.0atm\\V_2=?L

Putting values in above equation, we get:

3.8atm\times 7.6L=1.0atm\times V_2\\\\V_2=\frac{3.80\times 7.6}{1}=28.88L

Hence, the final volume of balloon is 28.88 L

sergejj [24]3 years ago
4 0
From the Boyle's law, it is clear that volume is inversely proportional to pressure. Thus it is prudent to say that, P1V1=P2V2
From the question above,
P1=1atm
P2=3.8atm
V1=?
V2=7.6L
Hence, 1*V1=3.8atm*7.6L
V1=28.88L
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Read 2 more answers
A mixture of sodium bicarbonate and ammonium bicarbonate is 75.9% bicarbonate by mass. what is the mass percent of sodium bicarb
Lorico [155]
Answer: 24.1%,  under below assumptions.

Justification:

The question is quite ambiguous, because one of the data is not clearly stated. It says that the mixture consists on two compounds:

- sodium bicarbonate, and
- ammonium bicarbonate

.After, it says that it is 75.9 % bicarbonate, but it does not specify which bicarbonate, it might be the sodium bicarbonate or the ammonium bicarbonate. It is apparent that you omitted that information by error.

Given that later, the question is <span>what the mass percent of sodium bicarbonate is in the mixture, it is supposed that the 75.9% content is of ammonium bicarbonate.

With that said, you can calculate the mass percent of sodium bicarbonate, because there are only two compounds and so you know that both add up the 100% of the mixture.

In formulas:

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=> % m/m sodium bicarbonate = 100% - % m/s ammonium bicarbonate

=> % sodium bicarbonate = 100% - 75.9% = 24.1%

Answer: 24.1%
</span>
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3 years ago
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